The mass is
0.330 mol Ca (40.08 g/mol) = 13.2 g Ca
To find the number of moles in 5000 grams of calcium, you need to divide the given mass by the molar mass of calcium. The molar mass of calcium is approximately 40.08 g/mol. So, 5000 grams of calcium is equal to 5000/40.08 = 124.69 moles of calcium.
The density of calcium is 1.55g/cc (1.55 grams per cubic centimeter). The mass depends on how large the quantity of calcium is.
The formula of anhydrous calcium chloride is CaCl2, and its gram formula mass is 110.99. The gram atomic mass of calcium is 40.08. Therefore, the grams of calcium in 100 grams of calcium chloride is 100(40.08/110.99) or 36.11 grams, to the justified number of significant digits.
The molar mass of calcium carbonate is 100.1 g/mol, and the molar mass of calcium oxide is 56.08 g/mol. Therefore, 12.25 grams of calcium carbonate would produce 6.86 grams of calcium oxide after decomposition.
To find the mass of calcium phosphate (Ca₃(PO₄)₂) in grams for 0.658 moles, first calculate its molar mass. The molar mass of calcium phosphate is approximately 310.18 g/mol. Multiply the number of moles by the molar mass: 0.658 moles × 310.18 g/mol ≈ 204.4 grams. Thus, there are about 204.4 grams of calcium phosphate in 0.658 moles.
To find the mass in grams of 0.330 mol of calcium, you need to multiply the number of moles by the molar mass of calcium. The molar mass of calcium is approximately 40.08 grams/mol. So, 0.330 mol * 40.08 g/mol = 13.23 grams of calcium.
To find the number of moles in 5000 grams of calcium, you need to divide the given mass by the molar mass of calcium. The molar mass of calcium is approximately 40.08 g/mol. So, 5000 grams of calcium is equal to 5000/40.08 = 124.69 moles of calcium.
The density of calcium is 1.55g/cc (1.55 grams per cubic centimeter). The mass depends on how large the quantity of calcium is.
To convert moles to grams, you use the molar mass of calcium. The molar mass of calcium is approximately 40.08 g/mol. Therefore, 1.3 moles of calcium would be 1.3 moles x 40.08 g/mol = 52.10 grams of calcium.
To find the number of moles in 3.75 grams of calcium, divide the mass of calcium by its molar mass. The molar mass of calcium is approximately 40.08 g/mol. Therefore, 3.75 grams of calcium is equal to 0.0936 moles.
The formula of anhydrous calcium chloride is CaCl2, and its gram formula mass is 110.99. The gram atomic mass of calcium is 40.08. Therefore, the grams of calcium in 100 grams of calcium chloride is 100(40.08/110.99) or 36.11 grams, to the justified number of significant digits.
There are 5 moles of calcium in 200 grams of calcium. This calculation is based on the molar mass of calcium, which is approximately 40 grams per mole.
The molar mass of calcium carbonate is 100.1 g/mol, and the molar mass of calcium oxide is 56.08 g/mol. Therefore, 12.25 grams of calcium carbonate would produce 6.86 grams of calcium oxide after decomposition.
For this you need the atomic mass of Ca. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel.40.0 grams Ca / (40.08 grams) = .998 moles Ca
To find the mass of calcium phosphate (Ca₃(PO₄)₂) in grams for 0.658 moles, first calculate its molar mass. The molar mass of calcium phosphate is approximately 310.18 g/mol. Multiply the number of moles by the molar mass: 0.658 moles × 310.18 g/mol ≈ 204.4 grams. Thus, there are about 204.4 grams of calcium phosphate in 0.658 moles.
To find the number of moles in 28 grams of calcium oxide, we need to divide the given mass by the molar mass of calcium oxide. The molar mass of calcium oxide (CaO) is 56.08 g/mol. So, 28 grams of CaO is equal to 28 g / 56.08 g/mol = 0.5 moles of calcium oxide.
To find the grams of phosphorus in calcium phosphide, first find the molar mass of calcium phosphide (Ca3P2 = 3Ca + 2P = 340.08 + 230.97 = 276.42 g/mol), then calculate the mass percent of phosphorus in calcium phosphide (2P/276.42 g/mol * 100%). Finally, determine the grams of phosphorus in 500 grams of calcium phosphide by multiplying the mass percent by 500 grams.