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To find the mass of calcium phosphate (Ca₃(PO₄)₂) in grams for 0.658 moles, first calculate its molar mass. The molar mass of calcium phosphate is approximately 310.18 g/mol. Multiply the number of moles by the molar mass: 0.658 moles × 310.18 g/mol ≈ 204.4 grams. Thus, there are about 204.4 grams of calcium phosphate in 0.658 moles.
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How many grams are in 6.4 moles of calcium phosphate?
To find the mass of calcium phosphate (Ca₃(PO₄)₂) in grams for 6.4 moles, first calculate its molar mass. The molar mass of calcium phosphate is approximately 310.18 g/mol. Therefore, the mass can be calculated by multiplying the number of moles by the molar mass: 6.4 moles × 310.18 g/mol = 1983.15 grams. So, there are approximately 1983.15 grams in 6.4 moles of calcium phosphate.
How many grams are in 2.3x10-4 moles of calcium phosphate?
To find the mass in grams of 2.3 x 10^-4 moles of calcium phosphate (Ca3(PO4)2), you first need its molar mass. The molar mass of calcium phosphate is approximately 310.18 g/mol. Therefore, the mass can be calculated as follows: 2.3 x 10^-4 moles × 310.18 g/mol ≈ 0.0713 grams.
How many grams of calcium phosphate are theoretically produced if you start with 10.3 moles of CaNO32 and 7.6 moles of Li3PO4?
735 g of Ca3(PO4)2 are obtained.
How many grams are in 120 grams of calcium?
120
How many grams in a tablespoon of calcium?
There are approximately 1.37 grams of calcium in one tablespoon of calcium citrate powder.
How many grams are in 6.4 moles of calcium phosphate?
To find the mass of calcium phosphate (Ca₃(PO₄)₂) in grams for 6.4 moles, first calculate its molar mass. The molar mass of calcium phosphate is approximately 310.18 g/mol. Therefore, the mass can be calculated by multiplying the number of moles by the molar mass: 6.4 moles × 310.18 g/mol = 1983.15 grams. So, there are approximately 1983.15 grams in 6.4 moles of calcium phosphate.
How many grams are in 2.3x10-4 moles of calcium phosphate?
To find the mass in grams of 2.3 x 10^-4 moles of calcium phosphate (Ca3(PO4)2), you first need its molar mass. The molar mass of calcium phosphate is approximately 310.18 g/mol. Therefore, the mass can be calculated as follows: 2.3 x 10^-4 moles × 310.18 g/mol ≈ 0.0713 grams.
How many gram of phosphorus are n 58.1 g of calcium phosphate?
58.1g [Ca(PO4)] X 1 mol [Ca(PO4)] X 2 mol (PO4) X 1 mol (P) X 30.97g (P) = 11.6g (P) 310.2g [Ca(PO4)] 1 mol[Ca(PO4)] 1 mol (PO4) 1 mol (P) Sorry about the formatting, im trying to show stoichiometry.
How many liters of water are required to dissolve 1 gram of calcium phosphate if solubility is 3.41 x 105?
To calculate the liters of water needed, first convert 1 gram of calcium phosphate into moles. Then, use the molar mass of calcium phosphate to convert moles into grams. Next, apply the solubility value to calculate the amount of calcium phosphate that can dissolve in 1 liter of water. This will give you the approximate amount of water needed to dissolve 1 gram of calcium phosphate.
How many moles of calcium are in 42.5 grams calcium?
42,5 grams calcium is equivalent to 1,06 moles.
How many grams of calcium phosphate are theoretically produced if you start with 10.3 moles of CaNO32 and 7.6 moles of Li3PO4?
735 g of Ca3(PO4)2 are obtained.
How many grams are in 120 grams of calcium?
120
How many grams in a tablespoon of calcium?
There are approximately 1.37 grams of calcium in one tablespoon of calcium citrate powder.
How many moles are there in 120 grams of calcium?
120 grams of calcium contain 2,994 moles.
How many moles in 200 grams of calcium?
There are 5 moles of calcium in 200 grams of calcium. This calculation is based on the molar mass of calcium, which is approximately 40 grams per mole.
How many grams calcium are in 100 grams calcium chloride?
The formula of anhydrous calcium chloride is CaCl2, and its gram formula mass is 110.99. The gram atomic mass of calcium is 40.08. Therefore, the grams of calcium in 100 grams of calcium chloride is 100(40.08/110.99) or 36.11 grams, to the justified number of significant digits.
How many atoms of calcium are in a unit of calcium Phosphate whose formula is Ca3 (PO4)2?
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