To find the mass of calcium phosphate (Ca₃(PO₄)₂) in grams for 0.658 moles, first calculate its molar mass. The molar mass of calcium phosphate is approximately 310.18 g/mol. Multiply the number of moles by the molar mass: 0.658 moles × 310.18 g/mol ≈ 204.4 grams. Thus, there are about 204.4 grams of calcium phosphate in 0.658 moles.
To find the mass in grams of 2.3 x 10^-4 moles of calcium phosphate (Ca3(PO4)2), you first need its molar mass. The molar mass of calcium phosphate is approximately 310.18 g/mol. Therefore, the mass can be calculated as follows: 2.3 x 10^-4 moles × 310.18 g/mol ≈ 0.0713 grams.
735 g of Ca3(PO4)2 are obtained.
120
There are approximately 1.37 grams of calcium in one tablespoon of calcium citrate powder.
120 grams of calcium contain 2,994 moles.
To find the mass in grams of 2.3 x 10^-4 moles of calcium phosphate (Ca3(PO4)2), you first need its molar mass. The molar mass of calcium phosphate is approximately 310.18 g/mol. Therefore, the mass can be calculated as follows: 2.3 x 10^-4 moles × 310.18 g/mol ≈ 0.0713 grams.
58.1g [Ca(PO4)] X 1 mol [Ca(PO4)] X 2 mol (PO4) X 1 mol (P) X 30.97g (P) = 11.6g (P) 310.2g [Ca(PO4)] 1 mol[Ca(PO4)] 1 mol (PO4) 1 mol (P) Sorry about the formatting, im trying to show stoichiometry.
To calculate the liters of water needed, first convert 1 gram of calcium phosphate into moles. Then, use the molar mass of calcium phosphate to convert moles into grams. Next, apply the solubility value to calculate the amount of calcium phosphate that can dissolve in 1 liter of water. This will give you the approximate amount of water needed to dissolve 1 gram of calcium phosphate.
42,5 grams calcium is equivalent to 1,06 moles.
735 g of Ca3(PO4)2 are obtained.
120
There are approximately 1.37 grams of calcium in one tablespoon of calcium citrate powder.
120 grams of calcium contain 2,994 moles.
There are 5 moles of calcium in 200 grams of calcium. This calculation is based on the molar mass of calcium, which is approximately 40 grams per mole.
The formula of anhydrous calcium chloride is CaCl2, and its gram formula mass is 110.99. The gram atomic mass of calcium is 40.08. Therefore, the grams of calcium in 100 grams of calcium chloride is 100(40.08/110.99) or 36.11 grams, to the justified number of significant digits.
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To find the number of moles in 5000 grams of calcium, you need to divide the given mass by the molar mass of calcium. The molar mass of calcium is approximately 40.08 g/mol. So, 5000 grams of calcium is equal to 5000/40.08 = 124.69 moles of calcium.