To find the mass in grams of 2.3 x 10^-4 moles of calcium phosphate (Ca3(PO4)2), you first need its molar mass. The molar mass of calcium phosphate is approximately 310.18 g/mol. Therefore, the mass can be calculated as follows: 2.3 x 10^-4 moles × 310.18 g/mol ≈ 0.0713 grams.
To find the mass of calcium phosphate (Ca₃(PO₄)₂) in grams for 0.658 moles, first calculate its molar mass. The molar mass of calcium phosphate is approximately 310.18 g/mol. Multiply the number of moles by the molar mass: 0.658 moles × 310.18 g/mol ≈ 204.4 grams. Thus, there are about 204.4 grams of calcium phosphate in 0.658 moles.
120 grams of calcium contain 2,994 moles.
735 g of Ca3(PO4)2 are obtained.
To find the number of moles in 5000 grams of calcium, you need to divide the given mass by the molar mass of calcium. The molar mass of calcium is approximately 40.08 g/mol. So, 5000 grams of calcium is equal to 5000/40.08 = 124.69 moles of calcium.
7,68 grams of calcium nitride is equal to 0,052 moles.
To find the mass of calcium phosphate (Ca₃(PO₄)₂) in grams for 0.658 moles, first calculate its molar mass. The molar mass of calcium phosphate is approximately 310.18 g/mol. Multiply the number of moles by the molar mass: 0.658 moles × 310.18 g/mol ≈ 204.4 grams. Thus, there are about 204.4 grams of calcium phosphate in 0.658 moles.
The balanced chemical equation for the reaction between calcium hydroxide and phosphoric acid is: 3Ca(OH)2 + 2H3PO4 -> Ca3(PO4)2 + 6H2O Using the mole ratio from the balanced equation, we find that 1 mole of calcium hydroxide reacts with 2/3 mole of calcium phosphate. First, calculate the number of moles of calcium hydroxide: 21.5g / 74.093g/mol = 0.290 moles Then, use the mole ratio to find the moles of calcium phosphate that can be produced: 0.290 moles * (1 mole Ca3(PO4)2 / 3 moles Ca(OH)2) = 0.097 moles Lastly, convert moles of calcium phosphate to grams: 0.097 moles * 310.176g/mol = 30 grams of calcium phosphate could be recovered.
Balanced equation first. Ca3(PO4)2 + 3H2SO4 -> 3CaSO4 +2H3PO4 1.523 moles H2SO4 (1 mole Ca3(PO4)2/3 moles H2SO4)(310.18 grams/1 mole Ca3(PO4)2) = 157.5 grams of Calcium phosphate
42,5 grams calcium is equivalent to 1,06 moles.
120 grams of calcium contain 2,994 moles.
735 g of Ca3(PO4)2 are obtained.
To calculate the number of moles in 150g of calcium phosphate, you need to first determine the molar mass of calcium phosphate (Ca3(PO4)2), which is 310.18 g/mol. Then, divide the given mass of calcium phosphate by its molar mass to get the number of moles. In this case, 150g / 310.18 g/mol ≈ 0.48 moles.
To find the number of moles in 5000 grams of calcium, you need to divide the given mass by the molar mass of calcium. The molar mass of calcium is approximately 40.08 g/mol. So, 5000 grams of calcium is equal to 5000/40.08 = 124.69 moles of calcium.
There are 5 moles of calcium in 200 grams of calcium. This calculation is based on the molar mass of calcium, which is approximately 40 grams per mole.
7,68 grams of calcium nitride is equal to 0,052 moles.
To convert moles to grams, you need to use the molar mass of aluminum phosphate. The molar mass of aluminum phosphate (AlPO4) is 122.98 g/mol. Therefore, 6.5 moles of aluminum phosphate would be 6.5 moles * 122.98 g/mol = 798.37 grams.
To convert moles to grams, you need to use the molar mass of the substance. The molar mass of aluminum phosphate is 122.94 g/mol. Therefore, for 5.5 moles of aluminum phosphate, you would have 5.5 moles x 122.94 g/mol = 676.17 grams of aluminum phosphate.