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The oxidation number of calcium in Ca3(PO4)2 is +2. This is because each phosphate ion (PO4)^3- has a charge of -3, and there are two phosphate ions in Ca3(PO4)2. Calcium has a +2 oxidation state to balance the -6 charge from the two phosphate ions.
To calculate the number of molecules in aluminum phosphate, we need to know the mass of the sample. Given the mass of aluminum phosphate, we can use Avogadro's number (6.022 x 10^23 molecules/mol) to calculate the number of molecules in the sample.
The balanced chemical equation for sodium phosphate reacting with calcium nitrate to produce sodium nitrate and calcium phosphate is: 2 Na3PO4 + 3 Ca(NO3)2 → 6 NaNO3 + Ca3(PO4)2. This equation is balanced because the number of atoms of each element is the same on both sides of the equation.
To find the number of atoms in 159g of calcium, you need to first calculate the number of moles of calcium present using the molar mass of calcium. The molar mass of calcium is approximately 40 g/mol. Then, you can use Avogadro's number (6.022 x 10^23 atoms/mol) to convert moles of calcium to atoms. Calculate the number of moles of calcium in 159g using the formula: moles = mass (g) / molar mass (g/mol). Finally, multiply the number of moles by Avogadro's number to determine the number of atoms in 159g of calcium.
To determine the number of atoms in 183g of calcium, you need to first calculate the number of moles of calcium using its molar mass (40.08 g/mol). Next, you can use Avogadro's number (6.022 x 10^23 atoms/mol) to convert moles of calcium to atoms. This will give you the number of atoms in 183g of calcium.
To find the mass of calcium phosphate (Ca₃(PO₄)₂) in grams for 0.658 moles, first calculate its molar mass. The molar mass of calcium phosphate is approximately 310.18 g/mol. Multiply the number of moles by the molar mass: 0.658 moles × 310.18 g/mol ≈ 204.4 grams. Thus, there are about 204.4 grams of calcium phosphate in 0.658 moles.
Calcium has valence of 2, forming the calcium ion Ca2+. The phosphate ion, PO43- contains five valent phosphorus and divalent oxygen along with three extra electrons. Compounds do not have a valence, atoms have a valence.
The oxidation number of calcium in Ca3(PO4)2 is +2. This is because each phosphate ion (PO4)^3- has a charge of -3, and there are two phosphate ions in Ca3(PO4)2. Calcium has a +2 oxidation state to balance the -6 charge from the two phosphate ions.
The formula unit for the most common form of calcium phosphate is Ca3(PO4)2. Therefore each formula unit, the ionically bonded counterpart of a mole for covalently bonded compounds, contains three calcium ions. The number of calcium ions in 8.0 "moles" of calcium phosphate is 3 [exact] X 8.0 X Avogadro's Number or 1.45 X 1025 atoms, where the depressed last digit of 1.45 indicates that this digit may not be significant. (The significant-digits-limiting datum is 8.0 moles.)
The balanced chemical equation for the reaction between calcium hydroxide and phosphoric acid is: 3Ca(OH)2 + 2H3PO4 -> Ca3(PO4)2 + 6H2O Using the mole ratio from the balanced equation, we find that 1 mole of calcium hydroxide reacts with 2/3 mole of calcium phosphate. First, calculate the number of moles of calcium hydroxide: 21.5g / 74.093g/mol = 0.290 moles Then, use the mole ratio to find the moles of calcium phosphate that can be produced: 0.290 moles * (1 mole Ca3(PO4)2 / 3 moles Ca(OH)2) = 0.097 moles Lastly, convert moles of calcium phosphate to grams: 0.097 moles * 310.176g/mol = 30 grams of calcium phosphate could be recovered.
To calculate the number of molecules in aluminum phosphate, we need to know the mass of the sample. Given the mass of aluminum phosphate, we can use Avogadro's number (6.022 x 10^23 molecules/mol) to calculate the number of molecules in the sample.
To calculate the atomicity of ammonium phosphate, first determine the formula of ammonium phosphate, NH4)3PO4. The atomicity is then determined by adding the total number of atoms in the formula, which is 12 (4 nitrogen atoms from ammonium and 8 atoms from phosphate). So, the atomicity of ammonium phosphate is 12.
The balanced chemical equation for sodium phosphate reacting with calcium nitrate to produce sodium nitrate and calcium phosphate is: 2 Na3PO4 + 3 Ca(NO3)2 → 6 NaNO3 + Ca3(PO4)2. This equation is balanced because the number of atoms of each element is the same on both sides of the equation.
To find the number of atoms in 159g of calcium, you need to first calculate the number of moles of calcium present using the molar mass of calcium. The molar mass of calcium is approximately 40 g/mol. Then, you can use Avogadro's number (6.022 x 10^23 atoms/mol) to convert moles of calcium to atoms. Calculate the number of moles of calcium in 159g using the formula: moles = mass (g) / molar mass (g/mol). Finally, multiply the number of moles by Avogadro's number to determine the number of atoms in 159g of calcium.
To determine the number of atoms in 183g of calcium, you need to first calculate the number of moles of calcium using its molar mass (40.08 g/mol). Next, you can use Avogadro's number (6.022 x 10^23 atoms/mol) to convert moles of calcium to atoms. This will give you the number of atoms in 183g of calcium.
Both ATP (adenosine triphosphate) and ADP (adenosine diphosphate) contain an adenosine molecule and a phosphate group. The main difference between ATP and ADP is the number of phosphate groups attached to the adenosine molecule. ATP has three phosphate groups, while ADP has two phosphate groups.
To determine the number of atoms in 133 g of calcium, you first need to calculate the moles of calcium using the molar mass of calcium, which is 40.078 g/mol. Then, you use Avogadro's number (6.022 x 10^23 atoms/mol) to convert moles to atoms. This will give you the number of atoms in 133 g of calcium.