Ca3P2 (Calcium Phosphide)
Molar Mass = 182 g
So 182 g cpd contains 62 g P
About 170.3 g
The hydrogen phosphide (syn.: phosphine, phosphane) has the chemical formula PH3.
4.00
28 grams calcium oxide (1 mole CaO/56.08 grams) = 0.50 moles CaO =============
5
10 milligrams
None. Hydrogen phosphide, more commonly called phosphine, contains only hydrogen and phosphorus.
Mg3P2 contains two atoms of phosphorous.
The daily requirement of phosphorus is 800. How many grams of phosphorus are needed?
A phosphorus atom gains three electrons to form a phosphide anion when forming a chemical bond to a metal.
The chemical formula for calcium phosphide is Ca3P2.Formula mass of Ca3P2 = 3(40.1)+2(31.0) = 182.3Amount of Ca3P2 = mass of sample / formula mass = 444/182.3 = 2.44mol
5000 grams calcium (1 mole Ca/40.08 grams) = 124.75 moles Calcium
42,5 grams calcium is equivalent to 1,06 moles.
The mass of phosphorus of any sample of calcium phosphate is the mass of the same multiplied by the percentage that phosphorus makes up of that sample. (mass of sample) x (mass of phosphorus/total mass) Therefore we must look at the chemical formula of the substance in question: Ca3(PO4)2. From this we can see that there are 2 phosphorus atoms attributing mass to the total molecule. The formula becomes: 500 g x 2x30.97 g/mol/310.17 g/mol = 99.8 g molar mass of phosphorus: 30.97 g/mol molar mass of calcium phosphate: 310.17 g/mol total mass: 500 g
Quite a few! 392 grams phosphorous (1 mole P/30.97 grams) = 12.7 moles phosphorous ===================
120
120 grams of calcium contain 2,994 moles.
126 grams calcium (1 mole Ca/40.08 grams) = 3.14 moles of calcium ------------------------------