The chemical formula for calcium phosphide is Ca3P2.
Formula mass of Ca3P2 = 3(40.1)+2(31.0) = 182.3
Amount of Ca3P2 = mass of sample / formula mass = 444/182.3 = 2.44mol
Wiki User
β 10y agoTo determine the number of moles of calcium phosphide in 444g, calculate the molar mass of calcium phosphide (Ca3P2), which is 182.181 g/mol. Then, divide the given mass by the molar mass to get the number of moles. So, 444g / 182.181 g/mol β 2.44 moles of calcium phosphide.
Ca3P3 is the chemical formula for calcium phosphide, a compound composed of calcium and phosphorus. It is often used as a pesticide and a rodenticide due to its toxic properties. Calcium phosphide reacts with water or moisture to produce phosphine gas, which is highly toxic to many organisms.
The molar mass of calcium carbonate (CaCO3) is 100.09 g/mol. Therefore, 2.8 moles of calcium carbonate would be 280.25 grams.
There are approximately 1 mole of calcium in 40 g, as the molar mass of calcium is about 40 g/mol.
To find the number of moles in 126g of calcium, divide the given mass by the molar mass of calcium (40.08 g/mol). 126g Ca / 40.08 g/mol = 3.14 moles of Ca.
To find the number of moles in 3.75 grams of calcium, divide the mass of calcium by its molar mass. The molar mass of calcium is approximately 40.08 g/mol. Therefore, 3.75 grams of calcium is equal to 0.0936 moles.
Ca3P3 is the chemical formula for calcium phosphide, a compound composed of calcium and phosphorus. It is often used as a pesticide and a rodenticide due to its toxic properties. Calcium phosphide reacts with water or moisture to produce phosphine gas, which is highly toxic to many organisms.
To find the grams of phosphorus in calcium phosphide, first find the molar mass of calcium phosphide (Ca3P2 = 3Ca + 2P = 340.08 + 230.97 = 276.42 g/mol), then calculate the mass percent of phosphorus in calcium phosphide (2P/276.42 g/mol * 100%). Finally, determine the grams of phosphorus in 500 grams of calcium phosphide by multiplying the mass percent by 500 grams.
42,5 grams calcium is equivalent to 1,06 moles.
0,27 moles of calcium contain 10,82 g calcium.
120 grams of calcium contain 2,994 moles.
3 moles of calcium is equivalent to 120,234 g.
29,0 g of calcium is equal to 0,723 moles.
425 g calcium (Ca) is equal to 10,604 moles.
0,06 g calcium is equivalent to 0,0015 moles.
400 g of calcium cabonate is equal to 3,996 moles.
120 g calcium is equal to 3 moles.
There is 1 mol of calcium atoms in 1 mol of calcium carbonate (CaCO3). Therefore, in 2.5 moles of CaCO3, there are 2.5 moles of calcium atoms.