To find the number of hydrogen atoms in 2.43 g of aspartame, calculate the number of moles of aspartame using its molar mass. Aspartame has a molar mass of 294.3 g/mol. Then, determine the number of moles of hydrogen atoms in one molecule of aspartame (the chemical formula of aspartame is C14H18N2O5). Finally, multiply the number of moles of aspartame by the number of moles of hydrogen atoms to find the total number of hydrogen atoms in 2.43 g of aspartame.
To find the number of moles in 10.0 g of aspartame, we first need its molar mass. Aspartame has a molar mass of approximately 294.3 g/mol. Using the formula: moles = mass (g) / molar mass (g/mol), we calculate: moles = 10.0 g / 294.3 g/mol, which is approximately 0.034 moles of aspartame.
Aspartame (C14H18N2O5) contains two nitrogen atoms per molecule. To find the number of nitrogen atoms in 1.2 g of aspartame, we first calculate the molar mass of aspartame, which is approximately 294.3 g/mol. Then, we determine the number of moles in 1.2 g of aspartame (1.2 g / 294.3 g/mol ≈ 0.00407 moles). Since each mole of aspartame contains 2 moles of nitrogen atoms, this results in approximately 0.00814 moles of nitrogen atoms, or about 4.9 x 10^21 nitrogen atoms.
The answer is 7,18.10e-10 moles.
10 g platinum is equal to 0,05 moles.
To determine the number of moles in 10 g of carbon, you need to know the molar mass of carbon, which is approximately 12 g/mol. By dividing the given mass by the molar mass, you can calculate that there are approximately 0.83 moles of carbon in 10 g.
10 moles of water (molar mass 18.0 g/mol) in 180 g, because 180 /18.0 = 10
There are 17 micromoles in 5.00mg of aspartame. 5.00mg has a molecular weight of 294.303 g/mol. Aspartame is composed of carbon, hydrogen, nitrogen and oxygen. The chemical formula for aspartame is C14H18N2O5. The molar mass is 294.30 g mol−1. There are 6.022 x 10 ^23 molecules in a mole
The chemical formula for aspartame is C14H18N2O5. The molar mass is 294.30 g mol−1. If we have 2.50 mg of aspartame, we have 8.495 x 10^-6 mol of aspartame. There are 6.022 x 10 ^23 molecules in a mole so we have 5.116 x 10 ^18 aspartame molecules. There are 18 H atoms per aspartame molecule so there are 9.028 x 10^19 H atoms present in 2.50 mg of aspartame.
10 moles of sodium chloride have 584,397 g.
To determine how many moles of PCl5 can be produced from 58.0 g of Cl2, we first need to calculate the moles of Cl2. The molar mass of Cl2 is approximately 70.9 g/mol, so the number of moles of Cl2 is 58.0 g / 70.9 g/mol ≈ 0.819 moles. The balanced reaction for the formation of PCl5 from P4 and Cl2 is: P4 + 10 Cl2 → 4 PCl5. From this, we see that 10 moles of Cl2 produce 4 moles of PCl5, so 0.819 moles of Cl2 can produce (0.819 moles Cl2) * (4 moles PCl5 / 10 moles Cl2) ≈ 0.3276 moles of PCl5. Thus, approximately 0.328 moles of PCl5 can be produced.
To find the molarity, first calculate the number of moles of aspartame. Given the molar mass of aspartame is 294.3 g/mol, you divide 15.0g by 294.3 g/mol to get 0.051 moles. Next, convert the solution volume to liters (250.00 mL = 0.250 L). Finally, divide the number of moles by the liters of solution to get the molarity, which is 0.204 M.