The answer is 7,18.10e-10 moles.
The number of molecules in 0.24 moles of oxygen can be calculated using Avogadro's number, which states that there are 6.022 x 10^23 molecules in one mole of any substance. Therefore, there are approximately 1.45 x 10^23 molecules of oxygen in 0.24 moles.
1.2 moles of oxygen atoms represent approximately 7.2 x 10^23 oxygen atoms. This is because 1 mole of any element contains Avogadro's number (6.022 x 10^23) of atoms. So, 1.2 moles would contain 1.2 times Avogadro's number of oxygen atoms.
The reaction is :- 2C2H6 + 7O2 ----------> 4CO2 + 6H2O When one mole ethane is combusted 7/2 moles of oxygen are used. When 3 moles of ethane are combusted 3 x 7/2 moles of oxygen used. No. of oxygen molecules consumed =6.022 x 1023 x7/2= 21.077 x 1023=2.107 x 1024 molecules.
To find the number of moles of atoms in 4.1 x 10^(-12) g of oxygen, you first convert the mass to moles by dividing by the molar mass of oxygen (16 g/mol). 4.1 x 10^(-12) g / 16 g/mol = 2.56 x 10^(-13) moles of oxygen atoms.
Divide that number by Avogadro's number: 3.968x10(23) / 6.02x10(23) = 0.659mol Mg, which would be about 16g.
23 moles of oxygen contain 138,509.10e23 molecules.
In 0.800 moles of MgO, there are the same number of oxygen atoms as there are in 0.800 moles of O atoms. One mole of MgO contains one mole of oxygen atoms, which is equivalent to 6.022 x 10^23 oxygen atoms.
very roughly 5 moles...avagadros number = 6.022 x 1023 just devide 30 by this number
In diphosphorous pentoxide (P4O10), there are 10 oxygen atoms for every molecule. Therefore, in 5.00 moles of diphosphorous pentoxide, there would be 5.00 moles x 10 oxygen atoms = 50.0 moles of oxygen atoms.
The number of molecules in 0.24 moles of oxygen can be calculated using Avogadro's number, which states that there are 6.022 x 10^23 molecules in one mole of any substance. Therefore, there are approximately 1.45 x 10^23 molecules of oxygen in 0.24 moles.
There are 2 atoms of oxygen in each molecule of silicon dioxide (SiO2). Therefore, in 0.100 moles of SiO2, there would be 0.100 moles * 2 atoms = 0.200 moles of oxygen atoms. Finally, since 1 mole of any element contains 6.022 x 10^23 atoms, there are (0.200 moles) * (6.022 x 10^23 atoms/mole) = 1.204 x 10^23 atoms of oxygen in 0.100 moles of silicon dioxide.
Ten million atoms / Avagadro's Number, 6.022e23 atoms per mole = 1.66e-17 moles
Ar of O = 16g/mol Mr of O2 = 2(16) = 32g/mol Using the formula : Number of moles = mass / Mr Number of moles = 40g / 32g/mol = 1.25mols One mole of substance contains the same number of particles as the Avogadro constant, which is 6.02 x 10^23 Number of Oxygen molecules = 1.25 x 6.02 x 10^23 = 7.525 x 10^23 Each Oxygen molecules contain two Oxygen atoms Number of Oxygen atoms = 7.525 x 10^23 = 1.505 x 10^24 atoms
1.2 moles of oxygen atoms represent approximately 7.2 x 10^23 oxygen atoms. This is because 1 mole of any element contains Avogadro's number (6.022 x 10^23) of atoms. So, 1.2 moles would contain 1.2 times Avogadro's number of oxygen atoms.
One mole is 6.02 × 1023 of anything. One mole of atoms is 6.02 × 1023 atoms, one mole of rice is 6.02 × 1023 grains, one mole of shoes is 6.02 × 1023 shoes.So you multiply 23 with 6.02 × 1023 to get 1.38 × 1025
There are 1.5 x 10^23 atoms of oxygen in 44g of CO2. This can be calculated by converting the mass of CO2 to moles, using the molar mass to find the number of moles of oxygen, and then multiplying by Avogadro's number to find the number of atoms.
1 mole of O2 has 6.023 x 1023 molecules. So, 23 moles of O2 will have 23 x 6.023 x 1023 molecules or 138.53 x 1023 molecules.