<html> <head> <title>asp</title> </head> <% dim f1,f2,f3,c f1=0 f2=1 response.Write(f1 &"<br>") response.write(f2 &"<br>") c=1 while(c<=10) f3=f1+f2 response.write(f3 &"<br>") c=c+1 f1=f2 f2=f3 wend %> </html>
Following logic for Fibonocci int f1=0; intf2=1; int i=0; while(i
Yes. F0, F1, F2, F3, F4, and F5. The ratings on what is called the Fujita scale are based on damage.
#include<stdio.h> #include<conio.h> int main(void) { int n,f1=0,f2=1,f3=0,i=1; printf("Enter the Number :\n\t\t"); scanf("%d",&n); printf("%d %d",f1,f2); while(i<=n-3) { f3=f1+f2; printf("%d",f3); f1=f2; f2=f3;i++; } getch(); }
f1 f2 f3 f4 f5
#include<stdio.h> #include<conio.h> void main() { int i,n,f1=0,f2=1,f3; clrscr(); for (i-0;i<10;i++) { f3=f1+f2; f1=f2; f2=f3; printf("%d \n",f3); } getch(); } output 1 2 3 5 8 13 21 34 55 89
Yes. Tornadoes can happen almost anywhere. The Reading area was affected by an F3 tornado in 1950, an F1 tornado in 1963, and an F2 tornado in 1979.
The F1, F2, and F3 designation on a dog breed designates the breeding. A Pure Bred Poodle and a Pure Bred Maltese makes a F1 MaltiPoo. When a MaltiPoo and MaltiPoo are bred, it gets a F2 designation.
You sum up the frequencies upto and including the current band. So if you have data bands b1, b2, b3 and so on with frequencies f1, f2, f3 etc then the cumulative frequency for b1 = f1 b2 = f1+f2 b3 = f1+f2+f3 and so on.
f1 f2 f3 f4 f5
class lift { public static void main(String args[]) { int f1,f2,f3; f1=1; f2=2; f3=3; ch=3; switch(ch) { case 1: f1=1; System.out.println(f1); break; case 2: f2=2; System.out.println(f2); break; case 3: f3=3; System.out.println(f3); break; default: System.out.println("remaining floors"); } } }
try this out...#include#includefloat valcal(float);int main(){float a,b,f,x,f1,f2,f3,i;a=2;b=3;int flag=0;f1=valcal(a);f2=valcal(b);printf("\n\n%f %f",f1,f2);for(i=0;i