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To determine the image distance (v) for an object placed at a distance (u) from a converging lens with a focal length (f), you can use the lens formula: ( \frac{1}{f} = \frac{1}{v} - \frac{1}{u} ). If both the object distance and focal length are given in centimeters, substitute those values into the equation to solve for v. Remember that the object distance is negative in the lens formula convention. The resulting image distance will indicate whether the image is real or virtual based on its sign.

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A converging lens of focal length f produces a real image of a real object when the object is what?

A real object placed beyond the focal length of a converging lens will produce a real image. This occurs when the object distance is greater than the focal length of the lens.


A converging mirror has a focal length of 20cm Where should an object be placed so that its virtual image will be twice as tall as the object?

10cm


How far should an object be placed from the pole of a converging mirror of focal length 20cm to form a real image of the size exactly one fourth the size of the object?

The object should be placed 10 cm away from the pole of the mirror to form a real image with a size exactly one fourth the size of the object. This is achieved using the mirror formula: 1/f = 1/v + 1/u, where u is the object distance, v is the image distance, and f is the focal length of the mirror.


What image is produced on a converging lens when an object is twice as far as the focal point?

An inverted and smaller real image is produced by a converging lens when an object is placed twice as far as the focal point. The image is located between the focal point and twice the focal length from the lens.


If an object is placed at a distance greater than twice the focal length of a convex lens what type of an image will be produced?

If an object is placed at a distance greater than twice the focal length of a convex lens, a real and inverted image will be produced. The image will also be smaller than the object.


When an object 5.0 cm tall is placed 12 cm from a converging lens an image is formed on the same side of the lens as the object but the image is 61 cm away from the lens. What is the focal length of t?

The image distance (61 cm) is positive since the image is on the same side of the lens as the object. Using the lens formula (1/f = 1/d_o + 1/d_i), where d_o is the object distance (12 cm) and d_i is the image distance, the focal length (f) of the lens is approximately 15 cm.


What type of image is produced by a converging lens on the screen?

A converging lens produces a real image on a screen when the object is placed beyond the lens's focal point. The image is inverted and can be larger or smaller, depending on the distance between the object and the lens.


An object is placed in front of a converging lens in such a position that the lens f 14.0 cm creates a real image located 27.0 cm from the lens Then with the object remaining in place the lens?

if ur asking what is the position of the object, you can use this formulas 1/f = 1/di + 1/do f: Focul length (14 cm) di: Image Distance (27 cm) do: Object distance (?) Object Distance ( do) = 4.69 cm


What is the only location a converging mirror will not produce an image?

A converging mirror will not produce a real image if the object is placed between the focal point and the mirror. In this case, the mirror will produce a virtual image on the same side as the object.


Choose the correct answer An erect object placed outside the focal poit of a converging lens will produce an image that is?

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What will the distance at which an object should be placed before the convex lens of focal length 12 cm yo obtain a real image of double its size?

The object should be placed at a distance of 18 cm from the convex lens to obtain a real image of double its size. This can be calculated using the lens formula: 1/f = 1/v - 1/u, where f is the focal length of the lens, v is the image distance, and u is the object distance.


What will the object distance be equal to when using concave mirror only?

When using a concave mirror, the object distance (distance of the object from the mirror) can vary depending on where the object is placed. If the object is located beyond the focal point of the mirror, the object distance will be positive. If the object is placed between the mirror and the focal point, the object distance will be negative.