The least common multiple (LCM) of 18 and 28 can be found by determining their prime factorizations. The prime factorization of 18 is (2 \times 3^2), and for 28 it is (2^2 \times 7). To find the LCM, take the highest power of each prime: (2^2), (3^2), and (7). Thus, the LCM is (2^2 \times 3^2 \times 7 = 4 \times 9 \times 7 = 252).
No because 280 mm equals 28 cm
To draw a rectangle with an area of 24 cm² and a perimeter of 28 cm, we need to find the dimensions that satisfy both conditions. Let the length be ( l ) and the width be ( w ). The area equation is ( l \times w = 24 ) and the perimeter equation is ( 2(l + w) = 28 ). From the perimeter, we get ( l + w = 14 ). Solving these two equations simultaneously, we can express ( w ) as ( w = 14 - l ) and substitute it into the area equation to find ( l ) and ( w ) are 6 cm and 4 cm, respectively. Thus, the rectangle can be drawn with dimensions 6 cm by 4 cm.
This question cannot be answered sensibly. The given measure, 28 cm x 18 cm is a measure of area, with dimensions [L2]. An inch is a measure of distance, with dimensions [L]. The two measure different things and basic dimensional analysis teaches that you cannot convert between measures with different dimensions such as these without additional information.
To create a rectangle with an area of 24 cm² and a perimeter of 28 cm, you can use the formulas for area (A = length × width) and perimeter (P = 2(length + width)). Let the length be ( l ) and the width be ( w ). From the area, we have ( lw = 24 ), and from the perimeter, ( 2(l + w) = 28 ) simplifies to ( l + w = 14 ). Solving these equations, you can find that ( l = 12 ) cm and ( w = 2 ) cm, or vice versa.
Suppose the Length and Width are L and W. Then Perimeter: 2(L + W) = 44 so that L + W = 22 and W = 22 - L and Area: L*W = 72 so that L*(22 - L) = 72 ie L2 - 22L + 72 = 0 (L - 4) (L - 18) = 0 Then L = 4 giving W = 18 or L = 18 giving W = 4 Since L > W (by convension), the answer is L =18 cm and W = 4 cm Substituting the
30=2(6)+2(l) 30=12+2(l) 18+2(l) length is 9 cm
Suppose the length is L cm. Then the width, W, is 2L/3 cm. Perimeter = 2(L+W) = 2(L+2L/3) = 10L/3 = 90 cm So L = 27 cm and W = 2L/3 = 18 cm.
P=2(w)+2(l) 52=2(12)+2(l) 52=24+2l 52-24=2l 28=2l 14=l The length is 14 cm.
It is impossible to say. Let L be ANY number such that 4.5 ≤ L < 9 cm and let B = (9 - L) cm. Then for every one of the infinite number of values of L, there will be a different rectangle whose perimeter will be 18 cm.
To calculate the surface area of a cone, you need the slant height (l), radius (r), and the height (h). Given the diameter of 18 cm, the radius is 9 cm (18 cm / 2). The surface area ( A ) is given by the formula ( A = \pi r (r + l) ). Substituting the values, ( l = 23 ) cm and ( r = 9 ) cm, the surface area is approximately ( A \approx 3.14 \times 9 \times (9 + 23) \approx 3.14 \times 9 \times 32 \approx 907.2 , \text{cm}^2 ).
Danny from L-A- - 2012 Hyuna 1-18 was released on: USA: 28 March 2013
100 cm = 1 metre so 28 cm = 28/100 = 0.28 metres. So simple!100 cm = 1 metre so 28 cm = 28/100 = 0.28 metres. So simple!100 cm = 1 metre so 28 cm = 28/100 = 0.28 metres. So simple!100 cm = 1 metre so 28 cm = 28/100 = 0.28 metres. So simple!