NaCl has a molar mass of 22,989 769 28 + 35,453 = 58,442 769 28 g
Na has an atomic weight of 22,989 769 28 g.
% Na = 22,989 769 28 ÷ 58,442 769 28 = 39,337
Mass of Na in 4,1 grams of NaCl = 0,39337 x 4,1 g = 1, 613 g
(7.6 g NaCl) (moles NaCl/58.44 g NaCl) (1 mole Na/1 mole NaCl) ( 22.99 g Na/mole Na) = 2.989 g Na or 3.0 g Na (significant figures) Steps: 1. Change everything to moles: use molar mass/molecular of NaCl 2. Find the molar ratio: since there are 1 Na in every NaCl, then the ratio of NaCl to Na is 1:1 3. Change moles back to grams: use the molar mass/molecular weight of Na 4. Watch out for significant figures! I hope this is right
Since NaCl is composed of one Na atom and one Cl atom, and the molar mass of Na is roughly 23 g/mol while that of Cl is about 35.5 g/mol, the molar mass of NaCl is approximately 58.5 g/mol. In 100 ppm NaCl, there are 100 mg of NaCl in 1 kg of solution. Therefore, the amount of Na in 100 ppm NaCl would be 100 mg * (23 g Na / 58.5 g NaCl) = ~ 39.3 ppm Na.
To find the number of moles of Na in 15 g of NaCl, you first need to calculate the molar mass of NaCl, which is 58.44 g/mol. Since Na makes up 39.34% of the molar mass of NaCl, you can calculate the moles of Na as (15 g / 58.44 g/mol) * 0.3934 = 0.255 moles of Na.
To determine the number of Na ions in 4.2 g of NaCl, we need to first calculate the amount of NaCl present. The molar mass of NaCl is 58.44 g/mol. This means that in 4.2 g of NaCl, there are 4.2/58.44 = 0.072 mol of NaCl. Since NaCl dissociates into 1 Na+ ion and 1 Cl- ion, there are 0.072 mol of Na+ ions in 4.2 g of NaCl. To find the number of Na+ ions, you would then multiply the number of moles by Avogadro's number (6.022 x 10^23).
To find the number of moles of Na in 42 grams, we can use the molar mass of Na, which is approximately 23 grams/mol. First, calculate the number of moles by dividing the given mass by the molar mass: 42 grams / 23 grams/mol = 1.83 moles of Na.
5 grams of table salt is 5 grams of NaCl. NaCl has a molar mass of 58.443 grams/mol, so 5 grams would be .0855 mol NaCl. In one mole of NaCl there is one mole of Na, so there would be .0855 mol Na, or 5.235 * 1022 atoms Na.
1 teaspoon of salt (NaCL) = 6 grams of NaCL or 2,360 mg of sodium (Na). (Na molecular wt is 23, Cl is 35.5, so NaCl is 58.5, so Na is 40 % times grams of wt of NaCl.) So 1 gram NaCl X 1 tsp/6 g NaCl = 0.16667 tsp NaCl or if you want Sodium ( how salt is expressed on food labels) then 1 gram of Na X 1 tsp NaCl/2.360 gram Na = 0.42 tsp Na.
[348 (g NACl)] * [23 (g/mol Na)] * [1 (mol NaCl/mol Na)] / [58.5 (g/mol NaCl)] = [348*23/58.5] = 136.8 = 137 g Na
145 grams NaCl (1 mole NaCl/58.44 grams)(1 mole Na +/1 mole NaCl)(6.022 X 1023/1 mole Na +) = 1.49 X 1024 ions of sodium =====================
(7.6 g NaCl) (moles NaCl/58.44 g NaCl) (1 mole Na/1 mole NaCl) ( 22.99 g Na/mole Na) = 2.989 g Na or 3.0 g Na (significant figures) Steps: 1. Change everything to moles: use molar mass/molecular of NaCl 2. Find the molar ratio: since there are 1 Na in every NaCl, then the ratio of NaCl to Na is 1:1 3. Change moles back to grams: use the molar mass/molecular weight of Na 4. Watch out for significant figures! I hope this is right
In 1 mol of NaCl there is 58.44 grams. ( 22.99 grams of Na + 35.45 grams of Cl). Using stoichiometry, you cancel the grams by taking 29.22 grams/58.44 grams. So 0.50 moles of NaCl
NaCl has a molar mass of 22,989 769 28 + 35,453 = 58,442 769 28 g Na has an atomic weight of 22,989 769 28 g. % Na = 22,989 769 28 ÷ 58,442 769 28 = 39,337 Mass of Na in 7,6 grams of NaCl = 0,39337 x 7,6 g = 2,99 g
Every mol of NaCl contains a mol of Na, weighting 23 grams, and a mol of Cl, weighing 35.5 grams. So, every mol of NaCl weights 58,5 (=23+35.5) grams. Therefore, 145 moles of NaCl weights 8482.5 grams.
I'll see if I can type it out for you.. 79g NaCl x (1 mol NaCl)/(58.44g NaCl) = 1.35 mol NaCl 1 mol NaCl = 58.44g (because Na is 22.99g and Cl is 35.45g)
To produce 4 grams of table salt (NaCl), you would need 2 moles of Na and 1 mole of Cl2. This corresponds to 46 grams of Na and 71 grams of Cl2. This would total 117 grams of reactants (2Na + Cl2) to produce 4 grams of NaCl.
For this you need the atomic mass of Na. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel.11.5 grams Na / (23.0 grams) = .500 moles Na
The molecular weight of sodium (Na) is 22.99 grams. The molecular weight of chlorine (Cl) is 35.45 grams. Therefore, there are 58.44 grams in 1 mole of NaCl. So, in 3.25 moles of NaCl, there are 58.44 gr x 3.25 = 189.93 grams.