7,5.1021 uranium atoms = 2,9644 grams
Well, Ca has an atomic mass of 40, so one mole of Ca (6.022x1023 atoms) equals 40g.To get 5kg of Ca, you would times the 40g (one mole) by 125.5kg of Ca has 125x(6.022x1023), or602200000000000000000000 atoms.
One mole is 6.02 × 1023 of anything. One mole of atoms is 6.02 × 1023 atoms, one mole of rice is 6.02 × 1023 grains, one mole of shoes is 6.02 × 1023 shoes.So you multiply 5 with 6.02 × 1023 to get 3.01 × 1024
3.49 x 10e22 carbon atoms x 1 mole of carbon / 6.02 x 10e23 carbon atoms equals 3.49/6.02 X 10e22/10e23 equals 0.579 X 10e-1 equals 5.79 X 10e-2 moles equals 0.0579 moles (3 significant figures)
To find the number of molecules of H2O2 in the vat, we first need to calculate the number of moles of oxygen atoms. Using the molar mass of oxygen (16 g/mol), we find that 455 grams of oxygen is equivalent to 28.44 moles. Since each molecule of H2O2 contains 2 oxygen atoms, the number of H2O2 molecules in the vat would be 2 times Avogadro's number (6.022 x 10^23) times the number of moles of oxygen atoms, or approximately 3.43 x 10^24 molecules.
You will need to convert to moles, and then atoms. Here is the equation: (5.10 grams over one) times (1 mol S over 32.06 g S) times (6.022 X 10 23 atoms over 1 mol S) the last part of the equation is read six point zero two two times ten to the twenty third.
14.17 x 15.00 = 212.55 Therefore the answer is 212.55 grams
There are 424 grams of oxygen in 477 grams of water. 8 times 53 equals 424.
20 g
The atomic mass of copper is approximately 63.55 g/mol. Therefore, the mass of 9 atoms of copper would be 9 times the atomic mass, which is 9 * 63.55 g/mol. This equals 571.95 grams.
To find the number of carbon atoms in 3 grams of carbon, first, we calculate the number of moles of carbon in 3 grams. The molar mass of carbon is approximately 12 grams per mole, so 3 grams of carbon is about 0.25 moles. Since one mole contains approximately (6.022 \times 10^{23}) atoms (Avogadro's number), multiplying 0.25 moles by (6.022 \times 10^{23}) gives approximately (1.51 \times 10^{23}) carbon atoms in 3 grams of carbon.
To find the mass of 2 grams of nitrogen (N) atoms, we first recognize that the atomic mass of nitrogen is approximately 14 grams per mole. Therefore, 2 grams of nitrogen corresponds to about ( \frac{2 , \text{g}}{14 , \text{g/mol}} \approx 0.143 , \text{moles} ) of nitrogen atoms. This means we have approximately ( 0.143 \times 6.022 \times 10^{23} \approx 8.6 \times 10^{22} ) nitrogen atoms in 2 grams.
To find the number of manganese atoms in 54.94 grams, you first need to know the molar mass of manganese, which is approximately 54.94 g/mol. This means that 54.94 grams of manganese corresponds to 1 mole of manganese atoms. Using Avogadro's number, which is approximately (6.022 \times 10^{23}) atoms/mol, there are about (6.022 \times 10^{23}) manganese atoms in 54.94 grams.
To calculate the number of atoms in 10 grams of gold, first determine the molar mass of gold, which is approximately 197 grams per mole. Using Avogadro's number, which is (6.022 \times 10^{23}) atoms per mole, you can find the number of moles in 10 grams of gold by dividing 10 grams by the molar mass (197 g/mol). Finally, multiply the number of moles by Avogadro's number to find the total number of atoms: [ \text{Number of atoms} = \left( \frac{10 \text{ g}}{197 \text{ g/mol}} \right) \times 6.022 \times 10^{23} \text{ atoms/mol} \approx 3.05 \times 10^{22} \text{ atoms}. ]
To find the number of atoms in 25.1 grams of sulfur, you first need to calculate the number of moles using the molar mass of sulfur (32.06 g/mol). Then, use Avogadro's number (6.022 x 10^23 atoms/mol) to convert moles to atoms. So, number of atoms in 25.1 grams of sulfur would be: ( \dfrac{25.1 , \text{g}}{32.06 , \text{g/mol}} \times 6.022 \times 10^{23} , \text{atoms/mol})
They are equal. Kilogram means thousand grams. 2.5 times 1000 equals 2500.
1 ounce = 28.35 grams.
To find the number of gold atoms in 45.0 grams of gold, first determine the molar mass of gold (Au), which is approximately 197 g/mol. Next, calculate the number of moles in 45.0 grams by dividing the mass by the molar mass: ( \frac{45.0 \text{ g}}{197 \text{ g/mol}} \approx 0.228 \text{ mol} ). Finally, multiply the number of moles by Avogadro's number ((6.022 \times 10^{23} \text{ atoms/mol})): ( 0.228 \text{ mol} \times 6.022 \times 10^{23} \text{ atoms/mol} \approx 1.37 \times 10^{23} \text{ atoms} ). Thus, there are approximately (1.37 \times 10^{23}) gold atoms in 45.0 grams of gold.