No. Iodine molecules are much larger in a molecular scale. This is due to the number of shells (6 shells) that iodine possess, making it an extremely large element, and its existence as I2 in nature makes it even larger. Water is made up of 2 hydrogen atoms and 1 oxygen atom, making it relatively smaller in comparison.
The boiling point of iodine (184.3 0C) is substantially higher than the boiling point of chlorine (-34 0C). Each element occurs at standard temperature and pressure as diatomic molecules; iodine molecules have substantially more mass than chlorine molecules; dispersion forces will be higher beween iodine molecules as they have more electrons than chlorine molecules. Both these factors contribute, mass will alomost certainly be the predominant factor.
Iodine is more soluble in kerosene than water because iodine is a nonpolar molecule, which is more attracted to the nonpolar molecules in kerosene than the polar molecules in water. This leads to stronger intermolecular forces between iodine and kerosene, allowing iodine to dissolve more readily in kerosene than in water.
In Sodium Chloride, Sodium ion (Na+) and Chloride ion (Cl-) are combined by ionic forces,Where as in Iodine Molecule Two Iodine atoms are combined by covalent bond.Covalent bond is always stronger than ionic Bond.So in water the weak bond (Ionic Bond) dissociates easily and Nacl Dissolves Readily compared to Iodine.
Iodine itself, I2 is not very soluble in water. However, the solubility of iodine can be greatly increased by adding potassium iodide to the reaction. The potassium iodide is broken apart into K+ and I-. The potassium ion is then dissolved into the water, and the iodine ion reacts with the I2 to form I3-. This I3- molecule is soluble in water. Therefore, the solubility is relative because I2 is not very soluble, but I3- is soluble, and both are made of nothing but iodine. Hope this helps.
Iodine's electron configuration is 2, 8, 18, 18, 7; bromine's is 2, 8, 18, 7. At the simplest level of modelling there is one more electron shell occupying space in an iodine atom than in one of bromine.
Iodine is not soluble in water because the intermolecular forces between iodine molecules (Van der Waals forces) are stronger than the forces between iodine and water molecules. This makes it difficult for iodine to break its solid lattice structure and separate into individual ions or molecules that can interact with water.
1) water 2) IKI 3) Glucose 4) Membrane pores 5) starch obviously starch is larger than the pores b/c it is the only substance that didn't pass through the membrane. glucose is the most complex molecule out of the remaining three, (making it 3rd smallest) and IKI is even less complex, and water is the most simple.
No, sand is not dissolved in water because sand has larger molecules than water molecules.
iodine is only very slightly soluble in water ( 0.03 g/100 cm3 water hand back data) this means solute-solute interactions are stronger than the solute-solvent interactions between iodine and water.
The boiling point of iodine (184.3 0C) is substantially higher than the boiling point of chlorine (-34 0C). Each element occurs at standard temperature and pressure as diatomic molecules; iodine molecules have substantially more mass than chlorine molecules; dispersion forces will be higher beween iodine molecules as they have more electrons than chlorine molecules. Both these factors contribute, mass will alomost certainly be the predominant factor.
Iodine is more soluble in kerosene than water because iodine is a nonpolar molecule, which is more attracted to the nonpolar molecules in kerosene than the polar molecules in water. This leads to stronger intermolecular forces between iodine and kerosene, allowing iodine to dissolve more readily in kerosene than in water.
Cells are larger than molecules. Cells normally have molecules inside them and constantly passing through their membranes. Cells normally contain water molecules along with glucose and other molecules.
9g of water
Bromine has more nuclear charge as compared to iodine. So, bromine easily attracts an electron and hence more reactive.
Smaller
In Sodium Chloride, Sodium ion (Na+) and Chloride ion (Cl-) are combined by ionic forces,Where as in Iodine Molecule Two Iodine atoms are combined by covalent bond.Covalent bond is always stronger than ionic Bond.So in water the weak bond (Ionic Bond) dissociates easily and Nacl Dissolves Readily compared to Iodine.
In other words this question asks if the pores are bigger or smaller than the iodine molecules. So.... the answer is that the iodine are smaller than the pores and the pores are bigger, because the iodine molecules need room to pass through, and the pores are not selectively permeable because they let the iodine through.