Ba(OH)2.8H2O is barium hydroxide octahydrate
Ba(OH)2
2KOH + Ba(NO3)2 -----> 2KNO3 + Ba(OH)2
Ba(NO3)2 + 2NaOH → Ba(OH)2 + 2NaNO3Barium nitrate + sodium hydroxide → barium hydroxide + sodium nitrate
Ba(OH)2(hydroxide) + H2SO4(acid) ==> BaSO4(salt) + 2H2O(water)
Ba(OH)2 (aq) + 2HCl (aq) --> BaCl2 (aq) + 2H2O (l)
The ions in Ba(OH)2 are: Ba(2+) and (OH)-.
Ba(OH)2 is the chemical formula barium hydroxide.
Ba is Barium, OH is Hydroxide and the 8 H2O is Octahydrate. This results in Barium Hydroxide Octahydrate.
The answer is 14 moles.
Balanced equation: Ba(OH)2 + 2HC2H3O2 ==> 2H2O + (C2H3O2)2BaSo, the mole ratio of Ba(OH)2 to HC2H3O2 is 1:2 so it takes 1/2 as much Ba(OH)2moles Ba(OH)2 needed = 1/2 x 0.452 = 0.226 moles Ba(OH)2
5.25 grams Ba(OH)2 (1mol Ba(OH)2/171.316 grams Ba(OH)2 ) = 0.0306 moles Ba(OH)2
NaOH and NaClAl(OH)3 and NaOHBa(NO3)2 and Al(OH)3Ba(OH)2 and Ba(NO3)2
Ba+2 OH-1
The answer is 0,123 mol.
Barium hydroxide IS soluble in water, and it has the formula Ba(OH)2, not ba(oh)2.
Ba(OH)2is the chemical formula of barium hydroxide.
Yes. Barium hydroxide, Ba(OH)², undergoes complete disassociation of its ions in water (Ba++ and 2 OH-).