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What is the mass of sulfur trioxide?
The molar mass of sulfur trioxide (SO3) is approximately 80.06 grams per mole.
What is the approximate percent by mass of oxygen in SO3?
The molar mass of SO3 is 80.06 g/mol, with oxygen contributing 48.00 g/mol, which is 60% of the total molar mass. Therefore, the approximate percent by mass of oxygen in SO3 is 60%.
6.11 mole of sulfur trioxide have a mass of how many grams?
Sulfur Trioxide has a molar mass of 80.0632 grams per mole. Therefore, 6.11 moles of Sulfur Trioxide is 489.186152 grams (without significant figures). With significant figures that would be 489 grams.
The compound whose formula is SO3 is called?
The compound with the formula SO3 is called sulfur trioxide.
What is the name of the compound SO3?
Sulfur tetraoxide 2- SO4 is sulfate
What is the percent sulfur in SO3?
Sulfur trioxide (SO3) contains about 40% sulfur by mass.
What is the percent by mass in sulfur in sulfur oxide?
The percent by mass of sulfur in a sulfur oxide compound can vary depending on the specific compound. For example, in sulfur dioxide (SO2), which contains one sulfur atom and two oxygen atoms, the percent by mass of sulfur would be approximately 50%. In sulfur trioxide (SO3), which contains one sulfur atom and three oxygen atoms, the percent by mass of sulfur would be approximately 40%.
What is the percent sulfur by weight in sulfur trioxide?
Sulfur trioxide (SO3) has a molar mass of 80.06 g/mol. The molar mass of sulfur (S) is 32.06 g/mol. Therefore, the percent sulfur by weight in sulfur trioxide can be calculated as: (32.06 g/mol / 80.06 g/mol) x 100 = 40%.
What is the mass of sulfur trioxide?
The molar mass of sulfur trioxide (SO3) is approximately 80.06 grams per mole.
What is the empirical formula of a compound that is 40 percent sulfure and 60 percent oxygen?
The empirical formula of the compound with 40% sulfur and 60% oxygen is SO3 (sulfur trioxide). The ratio of sulfur to oxygen in the compound is 1:3, which simplifies to SO3.
What is the approximate percent by mass of oxygen in SO3?
The molar mass of SO3 is 80.06 g/mol, with oxygen contributing 48.00 g/mol, which is 60% of the total molar mass. Therefore, the approximate percent by mass of oxygen in SO3 is 60%.
6.11 mole of sulfur trioxide have a mass of how many grams?
Sulfur Trioxide has a molar mass of 80.0632 grams per mole. Therefore, 6.11 moles of Sulfur Trioxide is 489.186152 grams (without significant figures). With significant figures that would be 489 grams.
What is the correct chemical formula for sulfur trioxide?
SO3 is the chemical formula for sulfur trioxide.
What is the percent (by weight) of oxygen in sulfur trioxide (SO3)?
The molar mass of SO3 is 80.06 g/mol. Oxygen makes up three of these four atoms, so the oxygen's molecular weight in SO3 is 48 g/mol (3 x 16). Therefore, the percent by weight of oxygen in SO3 is (48 g/mol / 80.06 g/mol) x 100% = 59.97%.
What is the compound for sulfur trioxide?
Formula: SO3
What is the empirical formula of a compound that is 4 percent sulfur and 6 percent oxygen by weight?
We can't tell. What's the other 90 percent? If you meant 40/60 instead... the mass of sulfur is twice that of oxygen, so a mass ratio of 40:60 is equivalent to an atom ratio of 1:3. The empirical formula would be SO3.
What is the Mass of a sulfur trioxide molecule?
The molar mass of sulfur trioxide (SO3) is approximately 80.07 grams per mole. This means that a single sulfur trioxide molecule has a mass of about 80.07 atomic mass units.
