Yes, it does.
yes
yes
It depends which 'other atom' it is
The formula for potassium chloride is KCl; one atom of potassium attaches to one atom of chlorine.Chlorine gas is diatomic (Cl2); thus, if there are 100 atoms of potassium to react, 100 atoms of chlorine will be needed. Therefore, 50 molecules of chlorine gas will be used.
Barium has two valence electrons and will lose both of them to form the Ba2+ ion. Iodine has seven valence electrons and so wil gain one for a full octet to forb the I- ion. Since the charges must be balanced in a chemical compound, two iodide ions must bond with one barium ion. So the Compound form is BaI2 rather than BaI.
Sulfur hexachloride is an inorganic compound consisting of two different elements. The prefix hexa indicates that there are six chloride atoms. Thus, the formula is SCl6. Note that this compound does not obey the octet rule.
No, metals tend to lose electrons to achieve a full octet.
Potassium has one valence electron that it would lose to become octet happy, or like a noble gas..therefore K(+1 charge)
KI ( potassium iodide) is an ionically bonded molecule. The metal potassium (K) ; kalium) ionises to form the potassium cation K^(+) The iodine atom has electron affinity to accept one electron into its outer energy shell to complete its octet, to form the iodide anion I^(-) .Since both these ions have a charge of '1' , but of opposite charge, they are attracted like the north and south poles of a magnet., to form the molecule potassium iodide (KI). Covalency and metallic bonding do not come into consideration. Hence K = K^(+) + e^(-) e^(-) + I = I^(-) 'Adding' K + I = K^(+) + I^(-) = K^(+)I^(-). shortened to KI
during the formation of calcium iodide,calcium donates two of its +ve ions each to a fluorine atom(2 in number) thereby making its octet and also fulfills the octet formation of each of fluorine atom..
The octet rule cannot be satisfied in molecules whose total number of valence electrons is an odd number.There are also molecules in which an atom has fewer, or more, than an octet of valence electrons.
potassium is a metallic element which belong to the group one metal like sodium ,so therefore potassium can only be a donor by combining with maganese. It does not have full octet stucture on it outer most shell.
It depends which 'other atom' it is
its called an octet
Na is Sodium (Nadium) K is Potassium (Kalium) They both produce positive ions. Na^(+) & K^(+) , and like magnets, where like poles repel and unlike poles attract, the are 'like ions' , Both positive, so they will repel and NOT combine. So the formula NaK doesnot exist .
No it is not fully obeying the octet rule. Boron has only 6 electrons (3 own + 3 from each F atom), lacking two for the octet. Fluorine is 3x satisfied, each with 8 electrons (each has 7 own plus 1 from boron).
BCl3 is the formula for Boron Chloride. As a matter of interest it does not obey the octet rule. It is also called a Lewis Acid.
There is ClO2 and ClO2^-. For the chlorite anion (ClO2^-) the Cl will have 10 electrons and will violate the octet rule. For ClO2, all elements will have 8 electrons.
Florine has, as you can see on your periodic table, 7 valance electrons. This means it has to take one into it's valance shell to form a stable octet. Potassium has a valence number of 1, so it has to donate 1 electron to have an octet. So, the ions look like this when donation and acceptance has occurred. K+ F- Put them together because opposite charges attract. KF potassium fluoride