Yes, it does.
A potassium atom has 1 electron in its outer shell. In order to satisfy the octet rule, it needs to donate 7 electrons to another atom to reach a stable configuration with a full outer shell.
The formula for potassium chloride is KCl; one atom of potassium attaches to one atom of chlorine.Chlorine gas is diatomic (Cl2); thus, if there are 100 atoms of potassium to react, 100 atoms of chlorine will be needed. Therefore, 50 molecules of chlorine gas will be used.
Barium has two valence electrons and will lose both of them to form the Ba2+ ion. Iodine has seven valence electrons and so wil gain one for a full octet to forb the I- ion. Since the charges must be balanced in a chemical compound, two iodide ions must bond with one barium ion. So the Compound form is BaI2 rather than BaI.
The potassium atom will form an ionic bond with the chlorine atom by transferring its valence electron to achieve a stable octet configuration. This results in the formation of a potassium ion (K+) and a chloride ion (Cl-), which are then attracted to each other due to their opposite charges.
PF5 obeys the octet rule as it has 5 bonding pairs of electrons around the central phosphorus atom, satisfying the octet. Cs2 does not follow the octet rule as Cs is in Group 1 and can only form ionic bonds. BBr3 is an exception to the octet rule as boron has only 6 electrons around it due to the empty d orbital. CO3 2- also obeys the octet rule as each oxygen atom has a complete octet.
KI ( potassium iodide) is an ionically bonded molecule. The metal potassium (K) ; kalium) ionises to form the potassium cation K^(+) The iodine atom has electron affinity to accept one electron into its outer energy shell to complete its octet, to form the iodide anion I^(-) .Since both these ions have a charge of '1' , but of opposite charge, they are attracted like the north and south poles of a magnet., to form the molecule potassium iodide (KI). Covalency and metallic bonding do not come into consideration. Hence K = K^(+) + e^(-) e^(-) + I = I^(-) 'Adding' K + I = K^(+) + I^(-) = K^(+)I^(-). shortened to KI
Potassium has one valence electron that it would lose to become octet happy, or like a noble gas..therefore K(+1 charge)
When scandium reacts with iodine, it will form the ionic compound scandium(III) iodide, with the formula ScI3. Scandium typically forms ionic compounds in which it loses its 3 valence electrons to achieve a stable octet configuration.
The octet rule cannot be satisfied in molecules whose total number of valence electrons is an odd number.There are also molecules in which an atom has fewer, or more, than an octet of valence electrons.
To make calcium iodide, calcium transfers two valence electrons to iodine. Calcium wants to lose two electrons to achieve a stable octet configuration, while iodine needs two electrons to complete its octet. This transfer results in the formation of CaI2 with a 2:1 ratio of calcium to iodine atoms.
potassium is a metallic element which belong to the group one metal like sodium ,so therefore potassium can only be a donor by combining with maganese. It does not have full octet stucture on it outer most shell.
1-I am not positive but I think I am correct
A potassium atom has 1 electron in its outer shell. In order to satisfy the octet rule, it needs to donate 7 electrons to another atom to reach a stable configuration with a full outer shell.
The charge on the potassium ion is +1, as it is a Group 1 element. The charge on the bromide ion is -1, as it gains one electron to achieve a full octet in its outer shell.
its called an octet
The Lewis dot structure for potassium plus bromine involves potassium donating its one valence electron to bromine. The resulting structure shows potassium with no dots and bromine with eight dots around it, satisfying the octet rule. This forms an ionic compound where potassium has a +1 charge and bromine has a -1 charge.
during the formation of calcium iodide,calcium donates two of its +ve ions each to a fluorine atom(2 in number) thereby making its octet and also fulfills the octet formation of each of fluorine atom..