r=E/I
N E R D s N E R D s
n e v e r r u n o u t
Power ( in watt) =Voltage (in Volt) x Current (in Ampere) P=V I We Know, V=I R So we can also write, P=I2 R or P=V2/ R
The heat released by the rheostat with double the voltage will quadruple. When voltage is tripled, the power loss is 32 or 9 times that before. A rheostat is a kind of variable resistor. Since E = IR (voltage equals current times resistance), then I = E/R (current equals voltage divided by resistance). If the voltage is doubled and the resistance stays the same, then--you can see by the formula--the current would double. Now, power dissipated by a resistor is related to the product of the current and voltage (P = IE). But since a doubling of voltage produces also a doubling of current, double the current results in 2X2=4 times the power (heat) loss.
disperse
You need to use the formula E = IR + Ir where: E is the e.m.f. of the power supply (the theoretical maximum voltage across the terminals when no current is flowing) I is current R is resistance of the circuit (load resistance) and r is the internal resistance of the power supply. Therefore, you can rearrange this formula to give r: E = IR + Ir (Subtract IR) E-IR=Ir (divide by I) (E-IR)/I=r or r=(E-IR)/I
You need to use the formula E = IR + Ir where: E is the e.m.f. of the power supply (the theoretical maximum voltage across the terminals when no current is flowing) I is current R is resistance of the circuit (load resistance) and r is the internal resistance of the power supply. Therefore, you can rearrange this formula to give r: E = IR + Ir (Subtract IR) E-IR=Ir (divide by I) (E-IR)/I=r or r=(E-IR)/I
The Ohm's law is defined as voltage propositional to current. The equation given by V=IR R IS THE PROPOSITIONAL CONSTANT
According to Ohm's law i.e. E=IR. When we increase resistance, keeping current constant, voltage will increase as in the above formula since E and R are directly proportional.
I = E/R or Current = Voltage/Resistance (Ohm's Law)
I=E/R You need to multiply both sides by R to get the R to reduce out of the right side. I*R=E
The formula for voltage is: E = I x R (E is voltage measured in volts, I is current measured in amperes or amps, R is resistance measured in ohms). Sample problem: An Mp3 player has 40 ohms of resistance and 0.1 amps of current flowing through it. What is the voltage that supplies the Mp3 player? Start with the formula, E = I x R. Put the values given into the formula: E = 0.1 x 40 Now, do the math: E = 4 volts
v=iR (v=potential difference two pts, R=resistance)
you need more information my way. you use 2 formula v=ir and p=i*i*r. i=current r=resistance v=voltage and p=power (heat given out)
Ohm's law - some times also represented as V = IR, where V is the Voltage, I is the Current and R being the Resistant (Constant). The law states that the current is directly proportional to the potential difference (voltage) across the two points. i.e. "I" is proportional to "V"
To obtain amperage from a formula you need at least two components. Formula for amperage are I = W/E, I = E/R and I = sq root of W/R.
E=IR.....So, R=E/I........ E volts diveded by I amps= resistance.... You do the math...