You need to use the formula E = IR + Ir
where: E is the e.m.f. of the power supply (the theoretical maximum voltage across the terminals when no current is flowing)
I is current
R is resistance of the circuit (load resistance)
and r is the internal resistance of the power supply.
Therefore, you can rearrange this formula to give r:
E = IR + Ir (Subtract IR)
E-IR=Ir (divide by I)
(E-IR)/I=r or r=(E-IR)/I
No, it is desirable for a battery to have a low internal resistance.
The value of internal resistance of 1.5 volt battery is 0.5 ohms.
unit of internal resistasnce is ohms too. V = I(R+r) V voltage across the circuit I current in the circuit R external resistance r internal resistance unit of internal resistasnce is ohms too. V = I(R+r) V voltage across the circuit I current in the circuit R external resistance r internal resistance
The total resistance of a circuit is the sum of the supply's internal resistance and its load resistance, because they are in series with each other. This is true regardless of the magnitude of, or the variation in, the current.
No, ammeters have a low internal resistance. This is so that when they are put in series with a circuit, they change the circuit's operating characteristics as little as possible.Contrast this with voltmeters, which do have a high internal resistance, and which are intended to be placed in parallel with the circuit they are measuring.Use the link below to the related question on why ammeters have a low internal resistance and read through that information to see why things are the way they are.
It depends on the application. Voltmeters have a high internal resistance, while ammeters have a low internal resistance.
No, it is desirable for a battery to have a low internal resistance.
The internal resistance of a device is the resistance in ohms of that device. It is the resistance electrons need to overcome before electricity is said to flow.
Resistivity effects internal resistance of a cell experiment by not allowing the cell to react. Internal resistance experiments are performed in advancing physics classes.
yes, batteries have high internal resistance. The higher the resistance the lower power you get out of the batter. Therefore if you no power you have very high resistance.
it is a type of resistance which inbuilt in voltage source
This question can be answered using voltage dividers. Assume the power supply consists of a voltage source and a resistor. With no load, all of the voltage source's voltage is dissipated by the internal resistor of 15V. When there is a load, there are two resistors in series. To calculate the internal resistance:1. I=V/R. You know the 600ohm resistor dissipated 13.7V. So that would mean a current of 13.7/600=22.8mA2. If the 600ohm resistor dropped 13.7, kirchoff's voltage law would tell us the internal resistor dropped 15-13.7=1.3V.3. R=V/I, Use the current to calculate the internal resistance. 1.3/22.8mA = 56.9ohmsCommentFurther to the above answer, a voltage-source's voltage is not 'dissipated by the internal resistance when on no load'. On no load, there is no current passing through the internal resistance, so no 'voltage dissipation' can takes plac -i.e. the non-load voltage is 15 V.
The value of internal resistance of 1.5 volt battery is 0.5 ohms.
ideal ammeter has zero internal resistance
"In short, it is 0.055555555555555555555555555555556OhmsYou can use ohms law to calculate this.You will use the formula: Resistance Equals Voltage Divided by Current.It is written: R=V/ISo use the numbers you provided, and the formula above.1.5 / 27 = 0.055555555555555555555555555555556"I dispute this answer. emf = I(R+r) is the actual equation u need. From this equation, u will find that V = emf - Ir. Ohm's law is not applicable for this situation. However I do think you will need a voltage to find the internal resistance.
internal resistance is always infinite in ideal current source .the internal resistance is in shunt with current source
no internal resistance of a cell cannot be considered to b as a defect because the resistance is so small as compared to the output we get from a cell this ristance can be neglected..