you have to write:
2NH4+3O2=2NO+4H2O
i think that's good;D
The equation for the thermal decomposition of ammonium diuranate (NH4)2U2O7 is: (NH4)2U2O7 → U3O8 + 2NH3 + H2O
The reactants of H2O are, of course, Hydrogen and Oxygen, but the chemical equation is not as simple to understand.The chemical equation of water is: H4+O2 ---> 2H2OIt is complicated to understand, but the O has to be changed to O2 in the reactants side due to the H2, which was changed to H4 in order to balance out the equation.
Ammonium oxalate monohydrate is (NH4)2C2O4•H2O
The balanced equation for this decomposition reaction is 2 H2O2 -> 2 H2O + O2.
So NH4Cl(s) -----> NH4+(aq) + Cl-(aq). As NH4Cl is ionic you can assume it is a solid. Since H2O is polar it reacts with the NH4Cl ion in a way which allows it to dissociate the ion. The oxygen is slightly negative while the hydrogens have a partial positive charge. The negativity of the oxygen in H2O causes the positive charge of the NH4+ molecule to cancel making it no longer attracted to the Cl. The hydrogen in H2O will do the same to the Cl. Once this happens you will have the products stated above in the reaction equation. NH4+ will further react with the water. NH4+ + H2O ---> NH3 + H3O+ . H3O+ is produced rather than OH- because NH4+ is acidic and therefore will donate a hydrogen. Note that because NH4Cl fully dissociates, you do not add in the + H2O in the first equation.
The equation for the thermal decomposition of ammonium diuranate (NH4)2U2O7 is: (NH4)2U2O7 → U3O8 + 2NH3 + H2O
The reactants of H2O are, of course, Hydrogen and Oxygen, but the chemical equation is not as simple to understand.The chemical equation of water is: H4+O2 ---> 2H2OIt is complicated to understand, but the O has to be changed to O2 in the reactants side due to the H2, which was changed to H4 in order to balance out the equation.
Ammonium oxalate monohydrate is (NH4)2C2O4•H2O
The chemical formula of ammonium oxalate monohydrate is (NH4)2C2O4·H2O. This compound contains two ammonium ions (NH4+), one oxalate ion (C2O4^2-) and one water molecule (H2O).
Formula of ammonium oxalate monohydrate: (NH4)2C2O4.H2O
The balanced equation for this decomposition reaction is 2 H2O2 -> 2 H2O + O2.
Nh3 + h2o-----> nh4oh ----->(nh4)^+ + (oh)^-
So NH4Cl(s) -----> NH4+(aq) + Cl-(aq). As NH4Cl is ionic you can assume it is a solid. Since H2O is polar it reacts with the NH4Cl ion in a way which allows it to dissociate the ion. The oxygen is slightly negative while the hydrogens have a partial positive charge. The negativity of the oxygen in H2O causes the positive charge of the NH4+ molecule to cancel making it no longer attracted to the Cl. The hydrogen in H2O will do the same to the Cl. Once this happens you will have the products stated above in the reaction equation. NH4+ will further react with the water. NH4+ + H2O ---> NH3 + H3O+ . H3O+ is produced rather than OH- because NH4+ is acidic and therefore will donate a hydrogen. Note that because NH4Cl fully dissociates, you do not add in the + H2O in the first equation.
In the reaction involving NH3 (ammonia) and H2O (water), the two Brønsted-Lowry acids are H2O and NH4+ (ammonium ion). H2O donates a proton (H+) to NH3, forming NH4+ and OH-. Thus, H2O acts as an acid by donating a proton, and NH4+ is the resultant acid formed in the reaction.
For the reaction 2 H2 + O2 -> 2 H2O, we see that 1 mole of O2 produces 2 moles of H2O. Therefore, to produce 10.2 moles of H2O, we would need 5.1 moles of O2.
Dissolving in water = splitting in ionsCH3COONH4 --> CH3COO- + NH4+CH3COO-, acetate is a weak base: CH3COO- + H2O CH3COOH + OH-NH4+, ammonium is a weak acid: NH4+ + H2O NH3 + H3O+Totally in water: CH3COO- + NH4+ CH3COOH + NH3 and 2H2O H3O+ + OH-
The balanced equation for the reaction of C6H12O6 with O2 to form CO2 and H2O is: C6H12O6 + 6 O2 -> 6 CO2 + 6 H2O