Add the mixture to water, Barium chloride is soluble and will dissolve while Silver chloride is insoluble and will remain in solid form.
No, not without a lot of work if you are referring to powdered samples. In aqueous solution you would get a blood red color due to the soluble complex, [Fe(SCN)2]-, a white solid due to insoluble AgCl formation, and another white solid due to insoluble AgSCN formation. You could filter the solution and recover the silver with a bit more work . . .
To prepare a dry sample of silver chloride, dissolve silver nitrate in water and add hydrochloric acid to form a white precipitate of silver chloride. Filter the precipitate, wash it with distilled water, and then dry it in an oven or desiccator to remove any remaining water.
Add hydrochloric acid to silver nitrate and stir well to ensure it is all reacted. Silver chloride will precipitate out and is fairly insoluble. Filter the solution and collect the filtrate on the filter paper. Rinse a few times with water to wash off the excess acid. Dry the filtrate in the oven. The result is pure silver chloride. Note this is sensitive to UV light, so this is best done in a dark room under a red lamp.
From the decomposition of barium phosphide (Ba3P2), barium (Ba) and phosphorus (P) would be formed.
Electrolysis can be used to separate copper from a mixture of powdered copper and sodium chloride. By passing an electric current through the mixture, the copper ions will be attracted to the negative electrode (cathode) where they will be reduced and deposited as solid copper. This process will allow the separation of copper from the sodium chloride.
One method to separate a mixture of barium sulfate and ammonium chloride, and lead chloride would be to use precipitation. By adding a solution of sodium sulfate (Na2SO4), barium sulfate will precipitate out due to its low solubility. The remaining solution can then be filtered to separate the lead chloride from the ammonium chloride.
Barium sulfate is insoluble in water; after filtration remain on the filter and sodium chloride pass as a solution.
The solubility of silver chloride in water is almost negligible. So it could be separated from water by filtration or evaporation.
Solid barium chloride can be distinguished by its white crystalline appearance and its solubility in water. When barium chloride is dissolved in water, a white precipitate of barium sulfate forms upon the addition of a sulfate-containing solution, due to the formation of a precipitate (BaSO₄) that is insoluble in water.
Not in its usual solid state. But like other ionic compounds calcium chloride will conduct electricity if molten or dissolved in water.
One common method to detect the presence of chloride ions is through a silver nitrate solution. When silver nitrate is added to a sample containing chloride ions, a white precipitate of silver chloride forms. Another method is ion chromatography, which can separate and detect chloride ions based on their different migration times in a chromatographic column.
No, not without a lot of work if you are referring to powdered samples. In aqueous solution you would get a blood red color due to the soluble complex, [Fe(SCN)2]-, a white solid due to insoluble AgCl formation, and another white solid due to insoluble AgSCN formation. You could filter the solution and recover the silver with a bit more work . . .
Water is deleted by heating and evaporation.
One way to differentiate between iron chloride and sodium chloride solutions is to perform a chemical test using silver nitrate. Iron chloride solution will form a white precipitate of silver chloride, while sodium chloride solution will not react with silver nitrate. Another method is to use a flame test: iron chloride imparts a yellow color to the flame, while sodium chloride does not.
To prepare a dry sample of silver chloride, dissolve silver nitrate in water and add hydrochloric acid to form a white precipitate of silver chloride. Filter the precipitate, wash it with distilled water, and then dry it in an oven or desiccator to remove any remaining water.
Zinc chloride is very soluble in water and silicon dioxide is not soluble. - Put the mixture of ZnCl2 and SiO2 in water - Wait for the dissolving of the ZnCl2 - Separate the two components by filtering
Add hydrochloric acid to silver nitrate and stir well to ensure it is all reacted. Silver chloride will precipitate out and is fairly insoluble. Filter the solution and collect the filtrate on the filter paper. Rinse a few times with water to wash off the excess acid. Dry the filtrate in the oven. The result is pure silver chloride. Note this is sensitive to UV light, so this is best done in a dark room under a red lamp.