Mass of hydrogen = 1 g/mol
Mass of oxygen = 16 g/mol
There are 2 hydrogen in H2O2 and 2 oxygen in H202, so
(1x2) + (16x2) = 34 g/mol
To calculate the amount of hydrogen peroxide (H2O2) dissolved, you can use the equation: moles of KMnO4 = moles of H2O2. Firstly, calculate the moles of KMnO4 (given concentration and volume). Then, use the balanced chemical equation to determine the moles of H2O2, as they have a 1:1 stoichiometric ratio. Finally, convert moles of H2O2 to grams using the molar mass to find the amount dissolved in the solution.
The chemical equation for the decomposition of H2O2 is 2 H2O2 -> 2 H2O + O2. This shows that two moles of H2O2 are required to produce each mole of O2. By definition, a 0.500 M solution of H2O2 contains 0.500 moles of H2O2 in each liter of solution. Solutions are always homogeneous; therefore, 50,0 mL of such a solution will contain (0.500)(50.0/1000) or 0.0250 moles of H2O2. As noted in the first paragraph, this will produce half as many, or 0.0125, moles of O2. The gram molar mass of O2 is twice the gram atomic mass of oxygen, or 31.9988. Therefore, decomposition of this amount of H2O2 will produce 31.9988 X 0.0125 or 0.400 gram of O2, to the justified number of significant digits.
If the density is 1.0 g/ml, one liter of the solution will weigh 1000 grams. 3.0 % of this mass or 30 grams of it is constituted of H2O2. The molar mass of H2O2 is 2 (1.008 + 15.999) = 34.014. The molarity of this solution is therefore 30/34.014 = 0.88, to the justified number of significant digits.
To calculate the amount of hydrogen peroxide (H2O2) needed to make a 1.33 molal solution in 1500 ml of water, you first need to convert the volume of water to grams. Since the density of water is 1.0 g/ml, 1500 ml of water is equal to 1500 grams. Next, calculate the moles of H2O2 needed using the molality formula (molality = moles of solute / mass of solvent in kg). Then convert the moles to grams by multiplying by the molar mass of H2O2 (34.02 g/mol).
To make a 500 ml solution of 3% H2O2 from a 50% solution, you would need to dilute the 50% solution with water. You would add 325 ml of water to 175 ml of the 50% H2O2 solution to achieve a final volume of 500 ml with a concentration of 3% H2O2.
To calculate the amount of hydrogen peroxide (H2O2) dissolved, you can use the equation: moles of KMnO4 = moles of H2O2. Firstly, calculate the moles of KMnO4 (given concentration and volume). Then, use the balanced chemical equation to determine the moles of H2O2, as they have a 1:1 stoichiometric ratio. Finally, convert moles of H2O2 to grams using the molar mass to find the amount dissolved in the solution.
The chemical equation for the decomposition of H2O2 is 2 H2O2 -> 2 H2O + O2. This shows that two moles of H2O2 are required to produce each mole of O2. By definition, a 0.500 M solution of H2O2 contains 0.500 moles of H2O2 in each liter of solution. Solutions are always homogeneous; therefore, 50,0 mL of such a solution will contain (0.500)(50.0/1000) or 0.0250 moles of H2O2. As noted in the first paragraph, this will produce half as many, or 0.0125, moles of O2. The gram molar mass of O2 is twice the gram atomic mass of oxygen, or 31.9988. Therefore, decomposition of this amount of H2O2 will produce 31.9988 X 0.0125 or 0.400 gram of O2, to the justified number of significant digits.
If the density is 1.0 g/ml, one liter of the solution will weigh 1000 grams. 3.0 % of this mass or 30 grams of it is constituted of H2O2. The molar mass of H2O2 is 2 (1.008 + 15.999) = 34.014. The molarity of this solution is therefore 30/34.014 = 0.88, to the justified number of significant digits.
To calculate the amount of hydrogen peroxide (H2O2) needed to make a 1.33 molal solution in 1500 ml of water, you first need to convert the volume of water to grams. Since the density of water is 1.0 g/ml, 1500 ml of water is equal to 1500 grams. Next, calculate the moles of H2O2 needed using the molality formula (molality = moles of solute / mass of solvent in kg). Then convert the moles to grams by multiplying by the molar mass of H2O2 (34.02 g/mol).
The mass percent of hydrogen in hydrogen peroxide (H2O2) is 5.88%. This is calculated by taking the total mass of hydrogen in one molecule of H2O2 (2.01 g) divided by the total molar mass of H2O2 (34.02 g/mol) and multiplying by 100.
To make a 500 ml solution of 3% H2O2 from a 50% solution, you would need to dilute the 50% solution with water. You would add 325 ml of water to 175 ml of the 50% H2O2 solution to achieve a final volume of 500 ml with a concentration of 3% H2O2.
30% h2o2+h2so4
H2O2 + 2 KI --> 2 KOH + I2
To calculate the molality of a solution, you divide the moles of solute by the mass of the solvent in kilograms. The formula for molality is: Molality (m) moles of solute / mass of solvent (in kg).
First, calculate the mass of glycerol in 100g of the solution: 48.0g glycerol/100g solution = 48.0%. Next, calculate the mass of water in 100g of the solution: (100g - 48.0g glycerol) = 52.0g of water. Calculate the moles of glycerol by dividing the mass of glycerol by its molar mass: 48.0g / 92.09g/mol = 0.521 mol. Calculate the molality by dividing the moles of solute by the mass of solvent in kg: 0.521 mol / 0.052 kg = 10 mol/kg.
calculate the mole fraction of benzene in solution containing 30% by mass in carbon tetra chlorid
H2o2 is used to give stress. The is also called hydrogen peroxide solution.