It might look like this: Fe2O3 + 3CO => 2Fe + 3CO2 The oxide of iron plus carbon monoxide yields iron and carbon dioxide. The key is that the carbon monoxide must "strip" all the oxygen from the iron oxide. Add as many CO molecules to the equation as needed to take up the oxygen from iron. We added the 3 in front of the CO to get 3CO. That results in the 3CO2 in the end product. We just need to add a 2 in front of the Fe to get 2Fe to balance the equation.
2 Fe2O3 + 12 HNO3 -> 4 Fe(NO3)3 + 6 H2O
The balanced equation for the reaction is: 3Fe2O3 + 3CO → 2Fe + 3CO2. This equation ensures that the number of atoms for each element is the same on both sides of the equation.
The balance equation would be 4Fe + 3O2 ==> 2Fe2O3, so the coefficients are 4, 3, 2.
Because C and Fe appear in uncombined, atomic form in this equation we can ignore them initially and just look at the Fe2O3 and CO2. There are an odd number of atoms of O in the Fe2O3 and a odd number in the CO2. If I just double the number of molecules of Fe2O3 going into the reaction then this will also double the number of atoms of oxygen, thereby making the number even(which is what I want, eh). Here's what I have so far:2 Fe2O3 + C -> Fe + CO2Because there are six oxygen atoms on the left there must be six on the right. Therefore there are three CO2 molecules:2 Fe2O3 + C -> Fe + 3 CO2Finally:Four Fe's going in means four must come out.Three C's coming out means three must go in.2 Fe2O3 + 3 C -> 4 Fe + 3 CO2
The balanced equation is 2Fe2O3 + 4Al ----> 2Al2O3 + 3Fe. The coefficient of Fe is 3.
2 Fe2O3 + 12 HNO3 -> 4 Fe(NO3)3 + 6 H2O
3Fe + 4(H2O) ---> Fe3O4 + 4(H2) You really should learn this, its not that hard =D
To balance the chemical equation for the reaction of Al and Fe2O3 to produce Al2O3 and Fe, you need to ensure that the number of atoms for each element is the same on both sides of the equation. First, write the unbalanced equation: Al + Fe2O3 -> Al2O3 + Fe. Then, adjust the coefficients of each compound until the number of atoms of each element balances out. Solution: 2Al + Fe2O3 -> Al2O3 + 2Fe.
The balanced equation for the reaction is: 3Fe2O3 + 3CO → 2Fe + 3CO2. This equation ensures that the number of atoms for each element is the same on both sides of the equation.
Yes
The balanced equation for this reaction is Fe2O3 + 3 H2O = 2 Fe(OH)3.
The chemical equation is:2 Fe + 3 Ag2O = 6Ag + Fe2O3
The balance equation would be 4Fe + 3O2 ==> 2Fe2O3, so the coefficients are 4, 3, 2.
Because C and Fe appear in uncombined, atomic form in this equation we can ignore them initially and just look at the Fe2O3 and CO2. There are an odd number of atoms of O in the Fe2O3 and a odd number in the CO2. If I just double the number of molecules of Fe2O3 going into the reaction then this will also double the number of atoms of oxygen, thereby making the number even(which is what I want, eh). Here's what I have so far:2 Fe2O3 + C -> Fe + CO2Because there are six oxygen atoms on the left there must be six on the right. Therefore there are three CO2 molecules:2 Fe2O3 + C -> Fe + 3 CO2Finally:Four Fe's going in means four must come out.Three C's coming out means three must go in.2 Fe2O3 + 3 C -> 4 Fe + 3 CO2
In the balanced chemical equation 4Fe + 3O2 -> 2Fe2O3, the coefficient in front of iron (Fe) is 4.
The balanced equation is 2Fe2O3 + 4Al ----> 2Al2O3 + 3Fe. The coefficient of Fe is 3.
If the moles of Fe2O3 are known, you would use the mole ratio from the balanced chemical equation for the reaction involving Fe2O3 and Fe. In the balanced equation, the mole ratio between Fe2O3 and Fe is 2:2, which simplifies to 1:1. This means that for every mole of Fe2O3, there is an equivalent mole of Fe.