There is no easy method to balancing equations, you just have to check each side of the equation to ensure that it has an equal number of each atom: 2K + 2H2O --------> H2 + 2KOH
To balance the equation CO2 + H2 ➝ CH3OH, you would need to first balance the carbon atoms, then the hydrogen atoms, and finally the oxygen atoms. In this case, the balanced equation would be: CO2 + 3H2 ➝ CH3OH + H2O.
The balanced equation is 2 C4H10 + 13 O2 -> 8 CO2 + 10 H2O.
To balance the chemical equation C6H12O6 + O2 → CO2 + H2O: Start by balancing the carbon atoms by placing a coefficient of 6 in front of CO2. Balance the hydrogen atoms next by placing a coefficient of 6 in front of the H2O. Lastly, balance the oxygen atoms by placing a coefficient of 6 in front of O2 on the left side of the equation. The balanced equation is: C6H12O6 + 6 O2 → 6 CO2 + 6 H2O
The balanced equation for the complete combustion of C18H36 is: C18H36 + 25.5 O2 → 18 CO2 + 18 H2O. This equation shows that every molecule of C18H36 reacts with 25.5 molecules of O2 to produce 18 molecules of CO2 and 18 molecules of H2O.
For KCl in water, the interaction is ion-dipole, which is a strong interaction. For CH2Cl2 in benzene, the interaction is dipole-dipole, which is weaker than ion-dipole. For C6H6 and CH3OH in H2O, the interaction is hydrogen bonding, which is stronger than dipole-dipole. Therefore, rank from weakest to strongest would be: CH2Cl2 in benzene, C6H6 and CH3OH in H2O, KCl in water.
To balance the equation CO2 + H2 ➝ CH3OH, you would need to first balance the carbon atoms, then the hydrogen atoms, and finally the oxygen atoms. In this case, the balanced equation would be: CO2 + 3H2 ➝ CH3OH + H2O.
its balanced
As with any combustion reaction you need to include oxygen. The full equation for methanol combustion is: CH3OH + 2 O2 --> CO2 + 2 H2O
CO2+H2O
NO. There is no chlorine on the reactant side, so it cannot be balanced.
You mean balance it? 2C2H6 + 7O2 -> 4CO2 + 6H2O
6CO2 + 6H20 +energy yields C6H12O6 + 6O2. This is the equation for photosynthesis.
The product in the reaction of CH4 + 2O2 => CO2 + 2H2O is carbon dioxide (CO2) and water (H2O).
CH4 + H2O -> CH3OH + CH3OCH3 Does not balance; Each compound on the product side has one Carbon and Hydrogen atom, so there must be one methane and water molecule per each DME and methanol molecule So the hydrogens are then impossible to balance as one methane molecule has four hydrogens add that to the two hydrogens from each water molecule thats 6. Methanol has four hydrogens - bearing in mind that 6 would be produced per molecule The reaction hence cannot be balanced 2 CH3OH -> H2O + CH3OCH3 is the sythesis of DME from its consituents, maybe there was a transcription error somewhere.
The reaction between sodium bicarbonate (NaHCO3) and nitric acid (HNO3) produces carbon dioxide (CO2), water (H2O), sodium nitrate (NaNO3), and some nitrogen oxides as byproducts.
The chemical reaction is:2 C8H18 +25 O2 = 16 CO2 + 18 H2O
No because you have an extra H. Sodium hydroxide is NaOH.