CH4 + H2O -> CH3OH + CH3OCH3
Does not balance;
Each compound on the product side has one Carbon and Hydrogen atom, so there must be one methane and water molecule per each DME and methanol molecule
So the hydrogens are then impossible to balance as one methane molecule has four hydrogens add that to the two hydrogens from each water molecule thats 6.
Methanol has four hydrogens - bearing in mind that 6 would be produced per molecule
The reaction hence cannot be balanced
2 CH3OH -> H2O + CH3OCH3
is the sythesis of DME from its consituents, maybe there was a transcription error somewhere.
The balanced chemical equation for the synthesis of methanol from carbon monoxide and hydrogen gas is: CO + 2H2 -> CH3OH
The number of oxygen atoms in a compound does not always directly predict its water solubility. In general, compounds containing more polar functional groups like hydroxyl groups (OH) tend to be more water-soluble. Therefore, from highest to lowest water solubility, it would be CH3OH (methanol) > CH3OCH3 (dimethyl ether) > CH4 (methane).
No, CH3OH is not an element. It is a compound with the chemical formula CH3OH, which represents methanol, a type of alcohol.
What is the balanced equation for Ch3COOH alone
CH3OH is a molecular compound. It is composed of covalent bonds between the carbon, hydrogen, and oxygen atoms, which involves the sharing of electrons between the atoms.
When methanol (CH3OH) reacts with sulfuric acid (H2SO4), it forms dimethyl ether (CH3OCH3) and water (H2O) as products. This reaction is known as the dehydration of methanol.
Co + 2h2 -> ch3oh All letters capitals!
To balance the equation CO2 + H2 ➝ CH3OH, you would need to first balance the carbon atoms, then the hydrogen atoms, and finally the oxygen atoms. In this case, the balanced equation would be: CO2 + 3H2 ➝ CH3OH + H2O.
The balanced equation between ethanoic acid (CH3COOH) and methanol (CH3OH) to form methyl acetate (CH3COOCH3) is: CH3COOH + CH3OH -> CH3COOCH3 + H2O.
Chloroform and methanol can react to form methyl chloroformate and hydrogen chloride in the presence of a base catalyst. The reaction equation is: CHCl3 + CH3OH → CH3OCOCl + HCl
The balanced chemical equation for the synthesis of methanol from carbon monoxide and hydrogen gas is: CO + 2H2 -> CH3OH
Methanol and water do not react they just form a very stable solution.
The number of oxygen atoms in a compound does not always directly predict its water solubility. In general, compounds containing more polar functional groups like hydroxyl groups (OH) tend to be more water-soluble. Therefore, from highest to lowest water solubility, it would be CH3OH (methanol) > CH3OCH3 (dimethyl ether) > CH4 (methane).
As with any combustion reaction you need to include oxygen. The full equation for methanol combustion is: CH3OH + 2 O2 --> CO2 + 2 H2O
To calculate the amount of NH3 needed to react with 21 grams of CH3OH, you first need to balance the chemical equation for the reaction. Then, you convert the mass of CH3OH to moles and use the mole ratio from the balanced equation to determine the moles of NH3 required. Finally, convert the moles of NH3 to grams using the molar mass of NH3.
There is no easy method to balancing equations, you just have to check each side of the equation to ensure that it has an equal number of each atom: 2K + 2H2O --------> H2 + 2KOH
Balanced equation first. 2CH4O + 3O2 -> 2CO2 + 4H2O 23.5 moles methanol (3 moles O2/2 mole CH4O) = 35.3 moles oxygen needed --------------------------------------