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na +i2
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∙ 10y ago
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How do you balance na plus i2 nai?
2Na+I2-->2NaI
Chemical formula for Sodium iodide?
Sodium + Iodine ----> Sodium Iodide2 Na + I2 ----> 2 NaI
What is the balance equation for hydrogen gas and iodine gas?
H2+i2->2hi
What is the formula for ionic compound formed between sodium and iodine?
Na + I -> NaI Na+ + I- -> NaI Ionic compounds are formed when electrons transfer between atoms, leaving ions behind. These ions then attract each other due to the opposite charges.
Balance chemical equation of sodium chloride plus potassium iodide?
KI + NaCl = KCl + NaI
How do you balance na plus i2 nai?
2Na+I2-->2NaI
Complete the balance of Br2 plus NaI?
Br2 + 2NaI -> 2NaBr + I2
How do you balance this equation Na ZnI NaI Zn?
Na and Zn are correct because they are elements. Na is monovalent so NaI is correct. Zn is divalent and so ZnI is incorrect and should be ZnI2 . So if we have ZnI2 we need 2 Na to remove the I2 . So balanced it becomes: 2Na + ZnI2 ----> 2NaI + Zn
Chemical formula for Sodium iodide?
Sodium + Iodine ----> Sodium Iodide2 Na + I2 ----> 2 NaI
Which process represents the ionization energy?
The answer is NOT a)a) I(g) + e → I-(g)b) I2(g) → 2I(g)c) I(g) → I+(g) + ed) Na(g) + I(g) → NaI(s)e) Na(s) + 1/2I2(s) → NaI(s)
What is the balanced chemical equation for the reaction that takes place between bromine and sodium iodide?
Sodium + Bromine ----> Sodium bromide2 Na + Br2 ----> 2 NaBr
Which process represents the electron affinity?
a) I(g) + e → I-(g)b) I2(g) → 2I(g) c) I(g) → I+(g) + ed) Na(g) + I(g) → NaI(s)e) Na(s) + 1/2I2(s) → NaI(s)The correct answer out of these choices is clearly a) I(g) + e → I-(g). That is the right answer.
How do you balance KI CI2 KCI I2?
CI2+KI=2KCI+I2
Is NaI ionic or molecular compound?
NaI is ionic as are all sodium (Na) compounds
Benzoic acid plus NaOH plus iodine?
C6H5COOH + NaOH + I2 -----------> C6H5COOI + NaI + H2O
What song goes Na Na Nai?
Probably an N Dubz song
Heat of formation of water?
) I(g) + e → I-(g)b) I2(g) → 2I(g)c) I(g) → I+(g) + ed) Na(g) + I(g) → NaI(s)e) Na(s) + 1/2I2(s) → NaI(s)Of these options the correct answer is e).
