I dont exactly know what the difference between the books are but you follow the standard procedure, using Q=mc(delta)T, where c is the specific heat of hcl and naoh, you can say that you assume the hcl and naoh take on the properties of water unless you know hwo to calculate it. Hope that helps
It yields HCl+CO2, CO2 is a by product of a neutralization reaction with HCl.HCl (hydrochloric acid) if neutralized (reacted) with NaHC03 (sodium bicarbonate) will yield NaCl (table salt) + H2O (water) + CO2 (carbon dioxide)
Mg + 2HCl → MgCl₂+ H₂ When a metal reacts with an acid a salt and hydrogen are produced.
A neutralization reaction, in which water and a salt are produced.In the case of HCl and NaOH, table salt, or NaCl(aq) is a product A neutralization reaction, in which water and a salt are produced. NH4+(aq) and OH-(aq) react with H+(aq) and Cl-(aq) to produce H2O(l) and NH4+(aq) and Cl-(aq). Or water and an aqueous solution of ammonium chloride.
to acidify it for chloride test. you would not use hydrochloric as it contains chloride and interferes with chloride test. It may also act as a catalyst for the chloride test too. as small amounts can act as a catalyst for ester formation in organic chemistry.
Hydrogen chloride in aqueous solution is commonly known as hydrochloric acid.
Calcium chloride solution is neutral.
Sodium hydroxide + Hydrochloric acid ----> Sodium chloride + Water It is a neutralization reaction and is also exothermic. Products are Sodium chloride and water.
sodium chloride"
The neutralization reaction of sodium hydroxide and hydrochloric acid will form sodium chloride (common salt) and water. NaOH +HCl --> NaCl+ H2O
It is an acid-base reaction and will form water and sodium chloride.
0.0932 L
2.04 g
5.53 g
Because sodium chloride solution in water is neutral.
0.0932 L
0.0532 L
0.0532 L