Use Avagadro's Number (NA) ... 6.02 X 10^23 atoms (molecules) per mole. so ... 4830 / 6.02 X 10E23 = a really small number Molar equivalent, which my office calculator won't handle. Dude, if you're doing Chemistry homework, you should know this.
We know for every 6.022 x 10^23 molecules, we have a mole of a substance, right? So if we have 3920molecules, we can use the above conversion factor to get: 3920 molecules CO2 x (1mol CO2/(6.022x10^23molecules CO2)) = 6.51 x 10^-21 moles CO2. There are three significant figures in this problem, from the 3929 molecules.
For this you need the atomic (molecular) mass of CO2. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. CO2=44.0 grams33.0 grams C / (44.0 grams) = .750 moles CO2
Carbon Dioxide-CO2 To get molecules, we must convert grams to moles and moles to atoms using Avogadro's number. Molar mass of CO2= C:12.0g+O:16.0gx2=44.0g CO2 25.0g CO2 | 1 mol CO2 | 6.02x10 23 molecules CO2 ------------------------------------------------------------------- = 3.42x10 23 molecules CO2 1 | 44.0g CO2 | 1 mol CO2 Now to get the number of oxygen atoms. Since there are 3 atoms in CO2 and 2 of them are oxygen, we will divide by 3 (1.14x10 23) and multiply by 2 (2.28 x10 23) So the number of oxygen atoms in 25.0 grams of CO2 is 2.28x10 23 or 228 000 000 000 000 000 000 000
molecular weight of carbon dioxide = 44u gram molecular weight of carbon dioxide = 44g given mass = 11g no. of moles = given mass divided by molar mass = 11 divided by 44 = 0.25moles.
The result will be 1 m3 of CO2 and 2 m3 of H2O gas (and 2 m3 of O2 will be consumed).This is determined by the stoichiometry of the balanced reaction:CH4 + 2O2 ---> CO2 + 2H2O
The answer is 88 moles.
0.75 moles CO2 x 6.02x10^23 molecules/mole = 4.5x10^23 molecules
Given the balanced equation2C3H8O + 9O2 --> 6CO2 + 8H2OTo find the number of moles CO2 that will be produced from 0.33 mol C3H8O, we must convert from moles to moles (mol --> mol conversion).0.33 mol C3H8O * 6 molecules CO2 = 0.99 mol CO2---------- 2 molecules C3H8O
12×1023 molecules
1 mole CO2 = 6.022 x 1023 molecules 2.4mol CO2 x 6.022 x 1023 molecules CO2/1mol CO2 = 1.4 x 1024 molecules CO2
The number of molecules is 0,90332112855.10e23.
We know for every 6.022 x 10^23 molecules, we have a mole of a substance, right? So if we have 3920molecules, we can use the above conversion factor to get: 3920 molecules CO2 x (1mol CO2/(6.022x10^23molecules CO2)) = 6.51 x 10^-21 moles CO2. There are three significant figures in this problem, from the 3929 molecules.
1 mol = 6.02 * 10^23 molecules 0.018 mol = 6.02 * 10^28 * 0.018 molecules 1.0836 * 10^27 molecules of CO2
3.74 moles CO2 (6.022 X 10^23/1mol CO2) = 2.25 X 10^24 molecules of carbon dioxide.
The number of molecules is 7,52767607125.10e23.
Each mole of a substance contains 6.022 E23 molecules or atoms of that substance. Four moles of H2O will contain 2.4088 E24 molecules.
For this you need the atomic (molecular) mass of CO2. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. CO2=44.0 grams33.0 grams C / (44.0 grams) = .750 moles CO2