0.75 moles CO2 x 6.02x10^23 molecules/mole = 4.5x10^23 molecules
To find the number of molecules in 0.75 g of ammonia, we need to first calculate the number of moles using the molar mass of ammonia (17 g/mol). Then we can use Avogadro's number (6.022 x 10^23 molecules/mol) to convert moles to molecules. In this case, the number of molecules in 0.75 g of ammonia would be approximately 1.26 x 10^22 molecules.
Molarity means moles per litre. So here you have to divide the moles by 75 and multiply by 1000. 0.5/75*1000, which is 6.667 molar.
One mole of a substance has 6.022 E23 units. This means that in .75 moles there are 4.52 E23 molecules.
There are 15 moles of HCl present in 75 mL of a 200 M solution. To calculate this, first convert 75 mL to liters (0.075 L), then use the formula Molarity = moles/volume to find moles. So, 200 M = x moles / 0.075 L. Solving for x gives you 15 moles of HCl.
To produce 525 grams of ammonia (NH3), you would need 25 moles of ammonia. Since the balanced chemical equation for the reaction between hydrogen and nitrogen to form ammonia is 3H2 + N2 -> 2NH3, you would need 75 moles of hydrogen molecules (H2) to produce 525 grams of ammonia. This is equivalent to 4,500 molecules of hydrogen.
To find the number of molecules in 0.75 g of ammonia, we need to first calculate the number of moles using the molar mass of ammonia (17 g/mol). Then we can use Avogadro's number (6.022 x 10^23 molecules/mol) to convert moles to molecules. In this case, the number of molecules in 0.75 g of ammonia would be approximately 1.26 x 10^22 molecules.
The chemical formula of carbon dioxide is CO2. This shows that each molecule of carbon dioxide contains two oxygen atoms. The formula mass is about* [12 + (2 X 16)] or 44. 75/44 is about 1.7; therefore the specified amount of carbon dioxide is that many moles of the gas. Oxygen normally exists as diatomic molecules, so that the number of molecules of oxygen gas required is the same as the number of moles of carbon dioxide produced. This number is about 1.7 times Avogadro's number, or about 1.02 X 1024. *The approximate atomic mass of carbon is 12 and that of oxygen is 16.
For this you need the atomic mass of He. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel.75.0 grams He / (4.00 grams) = 18.8 moles He
Molarity means moles per litre. So here you have to divide the moles by 75 and multiply by 1000. 0.5/75*1000, which is 6.667 molar.
75 grams water is equal to 4,166 moles.
6.02 X 1023 particles per mole X .75 moles = 4.52 X 1023 molecules.
One mole of a substance has 6.022 E23 units. This means that in .75 moles there are 4.52 E23 molecules.
There are 15 moles of HCl present in 75 mL of a 200 M solution. To calculate this, first convert 75 mL to liters (0.075 L), then use the formula Molarity = moles/volume to find moles. So, 200 M = x moles / 0.075 L. Solving for x gives you 15 moles of HCl.
To produce 525 grams of ammonia (NH3), you would need 25 moles of ammonia. Since the balanced chemical equation for the reaction between hydrogen and nitrogen to form ammonia is 3H2 + N2 -> 2NH3, you would need 75 moles of hydrogen molecules (H2) to produce 525 grams of ammonia. This is equivalent to 4,500 molecules of hydrogen.
To determine the number of gold atoms in the bracelet, first find the number of moles of gold present in the bracelet by multiplying the total moles of metal atoms by the percentage of gold. Then, use Avogadro's number (6.022 x 10^23) to calculate the number of gold atoms present in the bracelet.
To convert moles to grams, you need to use the molar mass of the compound. The molar mass of SO2 is approximately 64.07 g/mol. Multiplying the number of moles by the molar mass gives: 0.75 moles x 64.07 g/mol = 48.0525 grams of SO2.
The gram-molecular mass of H2O is 18.01. Therefore, 75.0 grams contains 75.0/18.01 = 4.16 moles. Each molecule contains two hydrogen atoms. Therefore, the number of hydrogen atoms = 2(4.16)(6.022 X 1023) = 5.01 X 1024 atoms.