BA and napht. are both soluble in ether but not in water, so you dissolve them into an amount of ether. Naph. is non-polar and is difficult to make polar but BA has a polar carboxylic acid group on it. So, if you add a strong base like NaOH to the dissolved mixture in a separatory funnel, the OH will deprotonate the BA and the Na counter ion will form sodium benzoate which is soluble in water.
Separate the two in the funnel into an aqueous layer (the benzoate) and an organic layer (the napht.) The napht. contained in the ether layer is usually dried with some anhydrous salt like sodium or magnesium sulfate, filtered then the ether is evaporated to recover the napht.
Now, all you need to do is get the benzoate to go back to being insoluble now that it is dissolved in water. Do this using strong acid, HCl, which will neutralize the any remaining NaOH (to form water and NaCl) and will also reprotonate the BA making it once again insoluble in water.
Filter the BA out of the aqueous solution to recover it (vacuum filtration works well). Hope this helps,
M.V.C.
There isn't such a thing as more aromatic. Something is aromatic or not. If you are referring to the stabilization due to aromaticity, naphthalene has more electrons in the stabilizing Pi-system is therefore more stabilized.
To make a 0.13 m solution of naphthalene with 100.0g of naphthalene, you would need to solve for the mass of sulfur required using the formula: Molarity = moles of solute / liters of solution. From there, you can convert moles to grams using the molar mass of sulfur to find the mass needed to dissolve in the 100.0g of naphthalene.
Nothing, Naphthalene is an organic compound and can not mixed with ionic compound KI.
Naphthalene is a non metal. It is an organic compound commonly used in moth ball manufacture.
The graph of the melting point and freezing point of naphthalene would show a plateau at the melting point, as the solid naphthalene transitions into the liquid phase, and a plateau at the freezing point, as the liquid naphthalene transitions back into the solid phase. The melting point and freezing point of naphthalene are the same at approximately 80 degrees Celsius.
Naphthalene is a fused ring hydrocarbon composed of two benzene rings. Each benzene ring contains 6 carbon atoms. Therefore, naphthalene contains a total of 10 carbon atoms.
Yes, naphthalene is aromatic. It consists of two-fused benzene rings, making it an aromatic hydrocarbon.
Organic solvents that can dissolve naphthalene include benzene, toluene, xylene, and tetrahydrofuran (THF). These solvents have a non-polar nature and are capable of breaking the intermolecular forces holding naphthalene together.
Yes, naphthalene is slightly soluble in pentane due to their similar nonpolar characteristics. However, naphthalene is more soluble in nonpolar solvents like hexane or benzene.
The molecular formula for naphthalene is C10H8. Naphthalene is a polycyclic aromatic hydrocarbon compound in which two benzene rings are fused together to form the structure of this compound.
Naphthalene would be most soluble in non-polar solvents such as benzene or hexane because it is a non-polar molecule. Polar solvents like water would not dissolve naphthalene well due to the lack of strong intermolecular interactions between the polar water molecules and the non-polar naphthalene molecules.
There isn't such a thing as more aromatic. Something is aromatic or not. If you are referring to the stabilization due to aromaticity, naphthalene has more electrons in the stabilizing Pi-system is therefore more stabilized.
Yes, resonance is possible in naphthalene. The pi-electrons in the benzene rings of naphthalene can delocalize and spread out across the rings, leading to resonance stabilization. This resonance contributes to the stability and unique chemical properties of naphthalene.
The total mass of solute and solvent is 8.76 + 84.5 = 93.26 g. Percentage of naphthalene = 8.76/93.26 x 100 = 9.39 %.
Naphthalene is not an element. Naphthalene is a combination of elements. Its formula is C10H8 and it is a compound, not an element.
ΔTf = Kf * molality Molar mass of naphthalene = 128.17 g/mol Moles of naphthalene = 5.00 g / 128.17 g/mol = 0.039 mol Molality = moles of naphthalene / kg of solvent = 0.039 mol / 0.444 kg = 0.088 mol/kg ΔTf = 4.90°C/m * 0.088 mol/kg = 0.432°C Freezing point of benzene is 5.5°C, so the freezing point of the solution is 5.5°C - 0.432°C = 5.068°C.
Naphthalene (C10H8) is most soluble in non-polar solvents such as benzene, toluene, and carbon disulfide due to its non-polar nature and aromatic structure. These solvents can efficiently dissolve naphthalene molecules due to their similar non-polar characteristics.