A battery, a potentiometer (pot) and a multimeter (DMM) with current measuring capability will do the trick. Include a switch if you want to. Your setup is dirt simple. Hook up the battery, pot (which is a variable resistor) and DMM (in ammeter mode) in series. Tweak the pot and watch the current go up and down. Be prepared to make some calculations as a battery and a pot, say a 5k or 10k component, will not allow a lot of current. You'll be working in milliamperes, or milliamps (mA). You don't want an experiment with lots of current because you'll have problems with making your battery last and avoiding a situation where your resistance is so low that the battery cannot maintain its rated voltage because you're drawing too much current out of it.
The ratio of potential difference to current in a circuit is known as resistance, measured in ohms (Ω). This relationship is described by Ohm's Law, which states that resistance equals voltage divided by current (R = V/I).
We need to find R equivalent at first then divide V from it to find the total current.Case 1: If resistances are connected in series.Then, R(eq.) = R1 + R2 = 500 + 1500 = 2000 ohmSo, Total current, I = V/R(eq.) = 10/2000 = 1/200 or 0.002 A.Case 2: If resistances are connected in parallel.Then, R(eq.) = (R1 x R2)/(R1 + R2) = (500 x 1500)/(500 + 1500) = 400 ohmSo, Total current, I = V/R(eq.) = 10/400 = 1/40 or 0.025 A.
In a parallel circuit, each load added subtracts from total resistance. When one or more loads is removed from a parallel circuit, the total resistance is increased, reducing the total amperage draw. The less resistance a load has, the more current can pass through. This is part of Ohm's law. The mathematical equation that describes Ohm's law is: I=V/R , where I is the current in amperes, V is the potential difference in volts,and R is a circuit parameter called the resistance For example : The humble light-bulb is rated by the watts it uses. The amount of watts used by a light-bulb is calculated using Ohm's law. With the resistance of the bulb's filament and the voltage the bulb is designed to operate with, one can derive the amperage the bulb will draw. The amperage is then multiplied by the voltage to show wattage. Using Ohm's law : With the resistance of a 40watt 120volt light-bulb, only 0.33amps is able to pass through the bulb's 363ohm filament at 120volts. A lamp that has two 40watt bulbs inplace, and the two bulbs are in parallel, the circuit will have a resistance of 179ohms and draw 0.67amps which is 80watts at 120volts.
Yes, a rheostat controls the strength of current by adjusting the resistance in a circuit. Increasing the resistance using a rheostat reduces the current flow, while decreasing the resistance increases the current flow.
One example is Newton's second law of motion, F = ma, which describes the relationship between an object's mass, acceleration, and the force acting on it. Another example is the ideal gas law, PV = nRT, which relates the pressure, volume, temperature, and number of moles of a gas in a closed system.
Not interested
ohms law.
take a glass of water and put on your older brother. he will beat you. this will show the law of motion.
To find the conductance using ohms law,you take the inverse of the resistance(/R)
Current
No.
no
punch your class teacher on his head . he will give you equal and opposite reaction
ohms=amps/volts Amps= volts/ohms Volts = Amps*Ohms
Ohms law does not consider inductance
Ohms law.
in transformer