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How does rubidium form an ion?

Updated: 11/21/2023
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8y ago

Best Answer

in the same way as sodium/potassium forms an ion.

Lithium has an electron configuration of 2,1

Sodium has an electron configuration of 2,8,1,

Potassium has an electron configuration of 2,8,8,1

Rubidium has an electron configuration of 2,8,8,18,1

Caesium has the electron configuration of 2,8,8,18,18,1

Notice in all cases the last number is '1'. This represents the outer most electron, shell with one electron. Since it is the outer most electron and is shielded by energy shells of electrons from the nucleus, this outer most electron is not strongly held to the atom. The atom readily releases this outermost electron , and the process is called ionisation.

Chemically it is represented by the formula

M(g) = M^+(g) + e^-

NB

'M' is an ATOM

'M^+' is an ION (Not an atom).

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lenpollock

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5mo ago
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11y ago

When rubidium (Rb, #37) forms an ion, it loses its one valence electron. Once it loses this electron, its protons (37) outnumber its electrons (36), which gives it a charge of +1.

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11y ago

Rubidium loses one electron to form Rb+ and achieve the electronic configuration of Krypton, a noble gas, [Ar] 3d10 4s2 4p6

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11y ago

It loses an electron to form Rb+ which has the electronic configuration of krypton

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8y ago

Rubidium ionizes by losing its one valence electron. Its charge is therefore +1, and the ion is isoelectronic with Kr.

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8y ago

Rubidium is a metal in group 1. It has one electron in its outermost energy level so it reacts by losing this electron to form an ion with a 1+ charge.

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8y ago

Losing an electron rubidium become the cation Rb+.

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7y ago

Yes; this compound is rubidium chloride, RbCl.

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13y ago

Rubidium forms the Rb+ ion.

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13y ago

+1 ion

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Q: How does rubidium form an ion?
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