Na atom ion has an electronic configuration 2,8,1
On losing one electron it forms Na+ cation, with the configuration of 2,8 thereby obeying octet rule.
Sodium has one electron in its outer shell, so it tends to lose that electron to achieve a full outer shell. This makes sodium more stable as it follows the octet rule by having a complete outer electron shell with eight electrons.
Sodium typically loses its one valence electron to achieve a stable electron configuration, resembling the nearest noble gas (Neon), thereby obeying the octet rule. This electron loss allows sodium to form a stable ionic bond with other elements by attaining a complete outer shell with 8 electrons.
Sodium (Na) has 1 electron in the 3s orbital and chlorine (Cl) has 7 electrons in the 3p orbital. Sodium gives away the one electron to Cl, leaving it with 8 electrons (octet) in the 2p orbital (like Neon). The chlorine takes that one electron giving it 8 electrons (octet) in the 3p orbital. The sodium then has a +1 charge, and the chloride ion now has a -1 charge. This is an ionic bond.
PF5 obeys the octet rule as it has 5 bonding pairs of electrons around the central phosphorus atom, satisfying the octet. Cs2 does not follow the octet rule as Cs is in Group 1 and can only form ionic bonds. BBr3 is an exception to the octet rule as boron has only 6 electrons around it due to the empty d orbital. CO3 2- also obeys the octet rule as each oxygen atom has a complete octet.
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According to the octet rule, sodium will lose its one electron to achieve a full outer energy level, making it stable. This forms a positively charged sodium ion with a stable electron configuration.
Each sodium atom will lose one electron to achieve a complete octet in its outer shell, as the octet rule dictates atoms will gain or lose electrons to achieve a stable electron configuration with 8 electrons in the outer shell.
Yes, the octet rule states that atoms tend to gain, lose, or share electrons in order to have a full outer shell with eight electrons, which is considered stable. This stability is achieved by achieving the electron configuration of a noble gas.
yes PCl3 obey octet rule there are 5 electrons in the valence shell of phosphorous it need 3 electron to complete its octet so it form bond with 3 chlorine after bond formation there are 8 electron in its octet it obey octet rule
Sodium conforms to the octet rule by losing one electron to achieve a full outer shell, becoming a positively charged ion. This electron loss allows sodium to reach a stable electron configuration similar to that of the nearest noble gas, achieving a more stable and lower energy state.
The octet rule is a rule in chemistry where elements want to form bonds to attain 8 electrons in their valence shell. An example of this would be sodium chloride. Bonds that don't have 8 electrons in their valence shell don't follow this rule
Sodium has one electron in its outer shell, so it tends to lose that electron to achieve a full outer shell. This makes sodium more stable as it follows the octet rule by having a complete outer electron shell with eight electrons.
Az important rule: any octet has to have eight parts, otherwise it is not an octet.
Sodium typically loses its one valence electron to achieve a stable electron configuration, resembling the nearest noble gas (Neon), thereby obeying the octet rule. This electron loss allows sodium to form a stable ionic bond with other elements by attaining a complete outer shell with 8 electrons.
no it does not follow octet rule
When sodium becomes an ion, it loses one electron to fulfill the octet rule. A neutral sodium ion has 11 electrons, so an ion will have 10.
No chlorine oxides will obey the octet rule.