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How many electrons are needed to fill the outer shell of sodium?
Two electrons are needed to fill the outer shell of a sodium atom. The outer shell for sodium is the 3s sublevel. A neutral sodium atom has one electron in its 3s sublevel. Since atoms undergo chemical bonding in order to gain a noble gas electron configuration, called an octet, sodium atoms will lose their single 3s electron, becoming sodium atoms with a 1+ charge. By doing this, sodium ions become isoelectric with the noble gas neon, and achieve an octet, becoming stable.
How many electrons must sodium lose before it has an octet?
Sodium must lose one electron to achieve a stable octet configuration since it has 11 protons and would complete its outer shell to achieve the stable electron configuration of the nearest noble gas, neon, with 10 electrons.
In naCL why would CL gain the electron?
Chlorine (Cl) would gain an electron in sodium chloride (NaCl) to achieve a full outer electron shell and attain a stable octet configuration, following the octet rule. By gaining an electron, chlorine becomes a chloride ion with a full outer shell, creating an ionic bond with the sodium cation to form a stable compound.
How does sodium obey the octet rule when reacting to form compounds?
Sodium typically loses its one valence electron to achieve a stable electron configuration, resembling the nearest noble gas (Neon), thereby obeying the octet rule. This electron loss allows sodium to form a stable ionic bond with other elements by attaining a complete outer shell with 8 electrons.
Why does sodium want to bond with chlorine?
Sodium wants to bond with chlorine to achieve a stable electron configuration. Sodium has one electron in its outer shell and can transfer this electron to chlorine, which lacks one electron in its outer shell. By transferring the electron, both sodium and chlorine can attain a full outer shell and achieve a more stable, lower energy state. This results in the formation of an ionic bond between sodium and chlorine to create sodium chloride (table salt).
Sodium has one electron in its outer energy level. According to the octet rule .?
According to the octet rule, sodium will lose its one electron to achieve a full outer energy level, making it stable. This forms a positively charged sodium ion with a stable electron configuration.
How many electrons will each atom either gain or lose in order to satisfy the octet rule of Na?
Each sodium atom will lose one electron to achieve a complete octet in its outer shell, as the octet rule dictates atoms will gain or lose electrons to achieve a stable electron configuration with 8 electrons in the outer shell.
How many electrons are needed to fill the outer shell of sodium?
Two electrons are needed to fill the outer shell of a sodium atom. The outer shell for sodium is the 3s sublevel. A neutral sodium atom has one electron in its 3s sublevel. Since atoms undergo chemical bonding in order to gain a noble gas electron configuration, called an octet, sodium atoms will lose their single 3s electron, becoming sodium atoms with a 1+ charge. By doing this, sodium ions become isoelectric with the noble gas neon, and achieve an octet, becoming stable.
Why does sodium become stable by losing one electron?
Sodium has 1 valence electron in its outer shell. By losing this electron, sodium achieves a full outer shell, which is more stable. This stable configuration is achieved by following the octet rule, where atoms tend to gain, lose, or share electrons to have 8 electrons in their outer shell.
How many electrons must sodium lose before it has an octet?
Sodium must lose one electron to achieve a stable octet configuration since it has 11 protons and would complete its outer shell to achieve the stable electron configuration of the nearest noble gas, neon, with 10 electrons.
How does sodium obey the octet rule when reacting to form products?
Sodium conforms to the octet rule by losing one electron to achieve a full outer shell, becoming a positively charged ion. This electron loss allows sodium to reach a stable electron configuration similar to that of the nearest noble gas, achieving a more stable and lower energy state.
In naCL why would CL gain the electron?
Chlorine (Cl) would gain an electron in sodium chloride (NaCl) to achieve a full outer electron shell and attain a stable octet configuration, following the octet rule. By gaining an electron, chlorine becomes a chloride ion with a full outer shell, creating an ionic bond with the sodium cation to form a stable compound.
Why does sodium give up an electron?
Sodium gives up an electron to achieve a stable electron configuration with a full outer shell. By losing the electron, sodium forms a positively charged ion, which allows it to achieve a more stable state by following the octet rule.
How does sodium obey the octet rule when reacting to form compounds?
Sodium typically loses its one valence electron to achieve a stable electron configuration, resembling the nearest noble gas (Neon), thereby obeying the octet rule. This electron loss allows sodium to form a stable ionic bond with other elements by attaining a complete outer shell with 8 electrons.
What charge do sodium form?
Sodium only has one electron in its outer energy level which it wants to lose in order to leave a stable octet of electrons in the level below. Loss of one electron causes a charge of plus 1 on the remaining ion.Magnesium has two electrons in its outer energy level, thus by losing these it takes on a charge of plus 2 and leaves a stable octet of electrons below in the next energy level.
Why does sodium want to bond with chlorine?
Sodium wants to bond with chlorine to achieve a stable electron configuration. Sodium has one electron in its outer shell and can transfer this electron to chlorine, which lacks one electron in its outer shell. By transferring the electron, both sodium and chlorine can attain a full outer shell and achieve a more stable, lower energy state. This results in the formation of an ionic bond between sodium and chlorine to create sodium chloride (table salt).
How does octet rules for formation of nacl?
Sodium (Na) has 1 electron in the 3s orbital and chlorine (Cl) has 7 electrons in the 3p orbital. Sodium gives away the one electron to Cl, leaving it with 8 electrons (octet) in the 2p orbital (like Neon). The chlorine takes that one electron giving it 8 electrons (octet) in the 3p orbital. The sodium then has a +1 charge, and the chloride ion now has a -1 charge. This is an ionic bond.
