Lewis dot structures are influenced by octet rule, when the electrons increase or decrease to fit into noble gas. Hence the chemical bonding in Lewis structure change.
It's hard I just am a kid who wanted to get my homework done.
See the Related Questions to the left for how to solve this problem.First draw the Lewis Dot structures of each molecule, then count the valence electrons of each atom in the structures. Find the one that doesn't have eight!In this case, there is actually a little trick. To follow the octet rule, each atom must have 8 valence electrons in the structure, right? Therefore, the molecule must have an even number of total electrons for that to work. So which molecule does not have an even number of total electrons?
I know for sure BBr# & PF5 do not obey the octet rule, but i can't remember the rule of isotopes so I can't say for sure whether or not CO3 -2 obeys it or not.
They do! Bonding with transition metals can definitely be drawn using Lewis dot structures. They are generally not taught until you reach high level chemistry courses however because they do not follow the 8-electron or octet rule as most other elements as taught in high school. Transition metals have valence bonding electrons in 3 different orbitals: s, p, and d(as opposed to say, carbon, oxygen, nitrogen, etc. that only have s and p valence orbitals). Because of the additional d-orbitals in transition metals, which can hold up to 10 electrons, transition metals follow what is known as the 18-electron rule (2 from the s-orbital plus 6 from the p-orbitals plus 10 from the d-orbitals. This 18-electron counting rule works the same as the octet rule, except now you need to use both your fingers and toes! ;-)
.. H - S - H (please see explanation below)*** .. *****The valence electron pairs are suppose to be on top and on bottom of the sulfur, instead of the hydrogen. This follows the octet rule for the sulfur and the duet rule for the hydrogen.
Flourins has 2s2 and 2p5 configuration and total 9 electrons in outermost shell. There are two possibilities for fluorine i.e. either to complete the outermost shell or to follow the octet rule. If it follow the octet rule there will remain 4 electrons in 2p. Hence its reactivity towards metals or other compounds will differ which is against its nature.Thats why flourine shows restrictions towards octet rule
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Octet rule states that each electron wants to complete its octet ( 8 electrons in the outermost shell) or a duplet (in case of hydrogen and helium).
They do, it's just that they do not follow the octet rule. You have to find the electron configuration to find the dot structure.
Hydrogen does not obey the octet rule. Boron does not always obey the octet rule and in fact forms Lewis acids such as BF3 which only has 6 electrons.
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H2S does follow the octet rule. When you draw the Lewis Structure for H2S, it looks like this: If you count up the lone pairs and sigma bonds (each worth 2), there are 8, thus, H2S follows the octet rule.
The elements can be described by dot structure. Metals combine with other elements to make its octet complete.
idk okay so 1st add 2 -3 /4
idk okay so 1st add 2 -3 /4
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There is ClO2 and ClO2^-. For the chlorite anion (ClO2^-) the Cl will have 10 electrons and will violate the octet rule. For ClO2, all elements will have 8 electrons.