6.45 moles X 6.02 X 10 to the 23 power will be right (use 3 significant figures in your answer)
n = (8.5 x 10^-5 g) x (1 mol / 28 g) = 3.04 x 10^-6 mol N = (3.04 X 10^-6 mol) x ((6.02 x 10^23 atoms)/(1 mol)) = 1.81 x 10^18 atoms
the constant Mole (mol): 6.02 x 10^23 are how many atoms you have per mol so the answer can be 7 mol atoms or 6.02 x 10^23 atoms per mol x 7 actual answer is 4.214 X10^24 atoms in 7 mol
Silicon is a common metalloid which is a chemical element but it is considered to be tetravalent metalloid which has only 4 available electrons for covalent chemical bonding in its valence region. In the periodic table, Silicon has atomic number 14 with Si symbol. It is good to know that silicon is less reactive that Carbon-14 based on its position in the periodic table which is in the bottom of Carbon. The Standard Atomic Weight for Silicon is 28.0855 grams. The standard is based on the Avogadro's Constant which is 6.02214179 x 1023 mol-1. 1 mol of silicon will contains 6.02214179 x 1023 atoms of silicon. So, how many atoms are present in 1 gram of silicon? In 1 mol silicon (28.0855 grams) = 28.0855/28.0855 x 6.02214179 x 1023 = 6.02214179 x 1023 atoms In 1 gram silicon = 1/28.0855 x 6.02214179 x 1023 = 2.144217404 x 1022 atoms
Silicon is a common metalloid which is a chemical element but it is considered to be tetravalent metalloid which has only 4 available electrons for covalent chemical bonding in its valence region. In the periodic table, Silicon has atomic number 14 with Si symbol. It is good to know that silicon is less reactive that Carbon-14 based on its position in the periodic table which is in the bottom of Carbon.The Standard Atomic Weight for Silicon is 28.0855 grams. The standard is based on the Avogadro's Constant which is 6.02214179 x 1023 mol-1. 1 mol of silicon will contains 6.02214179 x 1023 atoms of silicon. So, how many atoms are present in 12.5 gram of silicon?In 1 mol silicon (28.0855 grams) = 28.0855/28.0855 x 6.02214179 x 1023 = 6.02214179 x 1023 atomsIn 12.5 gram silicon = 12.5/28.0855 x 6.02214179 x 1023 = 2.680271755 x 1023 atomsRead more: How_many_silicon_atoms_are_there_in_1.00_g_of_silicon
There are 1.41 e24 atoms of Na in 2.35 mol of NaCl.
2.80x10^24 atoms x 1 mol/6.02x10^23 atoms = 4.65 moles
n = (8.5 x 10^-5 g) x (1 mol / 28 g) = 3.04 x 10^-6 mol N = (3.04 X 10^-6 mol) x ((6.02 x 10^23 atoms)/(1 mol)) = 1.81 x 10^18 atoms
Each mole of particles have 6.02 x 10^23 particles. (3.6 x 10^20) / (6.02 x 10^23) = 0.000598 mol of Silicon Ar of Si (Silicon) = 28.1g/mol mass = number of moles x Ar mass = 0.000598 mol x 28.1g/mol = 0.0168g of silicon
the constant Mole (mol): 6.02 x 10^23 are how many atoms you have per mol so the answer can be 7 mol atoms or 6.02 x 10^23 atoms per mol x 7 actual answer is 4.214 X10^24 atoms in 7 mol
Silicon is a common metalloid which is a chemical element but it is considered to be tetravalent metalloid which has only 4 available electrons for covalent chemical bonding in its valence region. In the periodic table, Silicon has atomic number 14 with Si symbol. It is good to know that silicon is less reactive that Carbon-14 based on its position in the periodic table which is in the bottom of Carbon. The Standard Atomic Weight for Silicon is 28.0855 grams. The standard is based on the Avogadro's Constant which is 6.02214179 x 1023 mol-1. 1 mol of silicon will contains 6.02214179 x 1023 atoms of silicon. So, how many atoms are present in 1 gram of silicon? In 1 mol silicon (28.0855 grams) = 28.0855/28.0855 x 6.02214179 x 1023 = 6.02214179 x 1023 atoms In 1 gram silicon = 1/28.0855 x 6.02214179 x 1023 = 2.144217404 x 1022 atoms
A mol = 6,022x10^23 atoms 1,5 mol = 9,033x10^23 atoms Always.
There are 1.204 x 1023 atoms in .200 mol of Pb.
Silicon is a common metalloid which is a chemical element but it is considered to be tetravalent metalloid which has only 4 available electrons for covalent chemical bonding in its valence region. In the periodic table, Silicon has atomic number 14 with Si symbol. It is good to know that silicon is less reactive that Carbon-14 based on its position in the periodic table which is in the bottom of Carbon.The Standard Atomic Weight for Silicon is 28.0855 grams. The standard is based on the Avogadro's Constant which is 6.02214179 x 1023 mol-1. 1 mol of silicon will contains 6.02214179 x 1023 atoms of silicon. So, how many atoms are present in 12.5 gram of silicon?In 1 mol silicon (28.0855 grams) = 28.0855/28.0855 x 6.02214179 x 1023 = 6.02214179 x 1023 atomsIn 12.5 gram silicon = 12.5/28.0855 x 6.02214179 x 1023 = 2.680271755 x 1023 atomsRead more: How_many_silicon_atoms_are_there_in_1.00_g_of_silicon
There are 1.41 e24 atoms of Na in 2.35 mol of NaCl.
0.45 mol BaSO4 have 2,698.10e23 sulfur atoms.
1.3 mol
The answer is 18,061.1023 atoms.