How many silicon atoms are there in 85.0 micrograms of silicon?

Answer 1

n = (8.5 x 10^-5 g) x (1 mol / 28 g) = 3.04 x 10^-6 mol

N = (3.04 X 10^-6 mol) x ((6.02 x 10^23 atoms)/(1 mol)) = 1.81 x 10^18 atoms

Answer 2

To find the number of silicon atoms in 85.0 micrograms of silicon, you would first calculate the moles of silicon using its molar mass. Then, you would use Avogadro's number (6.022 x 10^23 atoms/mol) to convert moles to atoms.