6.022 x 1023 molecules. This is Avogadro's number and a mole of anything. Since there are three atoms in each molecule, one of Barium and two of Chlorine, the number of atoms is three times that, or 1.807 x 1024.
Two
First, you want to figure out how many grams 1 mol of barium is. Look at the periodic table of elements. (www.webelements.com) Barium is Ba. Scroll down a little bit after clicking and you will see atomic weight. It is 137g. Now get the atomic weight for chlorine. It is Cl. The atomic weight is 35.5g. Just add them together. 137+35.5 = 172.5g = 1 mol of barium chloride. For 188g, just divide it by 172.5g. Which is 1.09 moles.
Since both barium chloride and barium sulfate contain one mole of barium atoms pert mole of compound, the moles of barium sulfate will be the same, 0.100, when barium has the limiting concentration in the production of the sulfate.
.256 molar= 256 mols of solute per 1000ml of solution. Since there are 1000ml in 1L, there are 256 mols of BaCl2 for every liter. Multiply this by 1.5 and you get a total of 384 mols of BaCl2 in 1.5L of a .256 molar solution
Since barium sulfate and barium chloride have a 1:1 molar ratio, you would need the same amount of barium chloride as barium sulfate, so 100 grams.
There are 2 atoms of chlorine and 1 atom of barium in each molecule of barium chloride (BaCl2). Therefore, in 0.550 mol of BaCl2, there are 0.550 mol x (1 Ba + 2 Cl) = 0.550 x 3 = 1.65 mol total atoms.
There are two chloride ions in one formula unit of barium chloride.
Totally three atoms One barium and two chlorine atoms
Barium gives its two electrons to two chlorine atoms (to form chloride ions) and they form an ionic compound barium chloride.
it is written barium chloride when a compound, and two. BaCl2 :)
Two atoms of chlorine are needed, one to accept each of the barium electrons in an ionic compound, barium chloride (BaCl2).
Two
To convert moles to grams, you need to use the molar mass of barium chloride, which is 208.23 g/mol. Multiply the number of moles (286 moles) by the molar mass to find the grams of barium chloride: 286 moles * 208.23 g/mol = 59,545.78 grams.
There are 2. The chemical formula tells you that there is 1 barium and 2 chlorine.
3,75 moles barium chloride
6,36 g of silver chloride are obtained.
In a chemical equation ,we must finish our chemical reaction with as many atoms of each element as when we started.the balanced chemical equation for the reaction of solid magnesium metal and barium chloride is given as .Mg + Bacl 2 -> Mgcl2 + Ba.