- Conversion factor needed = (6.022*1023 molecules S8 / 1 mole S8)
and (8 atoms S / 1 molecule S8)
calculate: 0.525 mol*(6.022 *10^23 molecules S8 / 1 mole S8) * (8 atoms S / 1 molecule S8) = 2.529... = 2.53 x 1024 atoms of S8 (3 Sig figs)
There are 2.21 x 10^24 atoms of phosphorus in 3.65 moles of phosphorus triiodide.
2,2 moles of plutonium: 13,248711938.1023 atoms.
If the chlorine is in its normal state of diatomic molecules, there are 16.0 moles of chlorine atoms in 8.00 moles of chlorine. The number of atoms is then 16 times Avogadro's number = 9.64 X 1024, to the justified number of significant digits.
There are 4.84 x 10^24 atoms present in 8.00 moles of zirconium because one mole of any element contains Avogadro's number of atoms, which is 6.022 x 10^23.
Since each N2O molecule contains 2 nitrogen atoms, the number of moles of N2O molecules would be half of the moles of nitrogen atoms. Therefore, in this case, there would be 2.615 moles of N2O molecules present in the sample.
0.0845 moles of tungsten is equal to 0,50887.10e23.
4,37.10e-18 C atoms are equivalent to 7,25.10e-6 moles.
4,80 moles of Fe contain 28,9062761136.10e23 atoms.
1. Three moles of sodium contain 18,06642387.1023 atoms. 2. The mass of three moles of sodium is 68,97 grams.
five
2 moles of benzene gives 12 moles of hydrogen atoms since benzene is C6H6
There are 2.21 x 10^24 atoms of phosphorus in 3.65 moles of phosphorus triiodide.
3KNO3, so 9 oxygen atoms.
2,2 moles of plutonium: 13,248711938.1023 atoms.
4.2 moles of CS2 contain 8,4 moles sulfur.
If the chlorine is in its normal state of diatomic molecules, there are 16.0 moles of chlorine atoms in 8.00 moles of chlorine. The number of atoms is then 16 times Avogadro's number = 9.64 X 1024, to the justified number of significant digits.
There are 4.84 x 10^24 atoms present in 8.00 moles of zirconium because one mole of any element contains Avogadro's number of atoms, which is 6.022 x 10^23.