For the isotope plutonium-239: cca. 2,52.1021atoms.
It depends on the atomic mass of a substance. To find out, divide the 1 by the atomic mass of the element (found on the periodic table), then multiply by 6.02*1023. Ag=(1/Am)*6.02*1023 Where Am=atomic mass of the element, and Ag=the number of atoms in a gram.
There are 6.022 x 10^22 atoms of sulfur in 1 gram, which is equivalent to Avogadro's number for a single element sulfur.
1 gram molybdenum (1 mole Mo/95.94 grams)(6.022 X 1023/1 mole Mo) = 6 X 1021 atoms of molybdenum ========================
1 gram phosphorus (1mol P/30.97 grams)(6.022 X 10^23/1mol P) = 1.9 X 10^22 atoms of phosphorus
* Approx. 115 US $/kg of the unrefined oxide U3O8 (but not for the nuclear grade, which is more expensive) - in July 2011. * The price of plutonium is probably 4 000 US $/g; the price depends on the isotopic composition and purity (nuclear fuel grade, weapons grade).
x/2
There are approximately 6.022 x 10^22 atoms in 1 gram of sulfur based on Avogadro's number, which is the number of atoms or molecules in one mole of a substance.
Impossible, no link
The price is estimated at 4 000 $.
The answer is 4,745.10e21 atoms.
1 gram = 1000 mg
There are 6.02 x 10^23 atoms of calcium in 1 gram of calcium.
It costs $280 per gram, it is one of the most expensive elements.
There are 15.432 grains in one gram224 grains=1 dwt / 1 { pennyweight } =.05 troy ounce / 1 gram=.643 pennyweight / 1 grain = 0.0648 grams / 4 grains = 1 carat / 15.432 grains = 1 Gram
It depends on the atomic mass of a substance. To find out, divide the 1 by the atomic mass of the element (found on the periodic table), then multiply by 6.02*1023. Ag=(1/Am)*6.02*1023 Where Am=atomic mass of the element, and Ag=the number of atoms in a gram.
1 gram H2 (1 mole H2/2.016 grams)(6.022 X 1023/1 mole H2) = 3 X 1023 atoms of hydrogen gas =========================
To find the number of atoms in 1 gram of calcium, you can use Avogadro's number and the molar mass of calcium. The molar mass of calcium is approximately 40.08 grams per mole. Therefore, 1 gram of calcium is about 0.0249 moles (1 g / 40.08 g/mol). Multiplying this by Avogadro's number (approximately (6.022 \times 10^{23}) atoms/mole) gives roughly (1.50 \times 10^{22}) atoms in 1 gram of calcium.