1 gram phosphorus (1mol P/30.97 grams)(6.022 X 10^23/1mol P)
= 1.9 X 10^22 atoms of phosphorus
There are 2.21 x 10^24 atoms of phosphorus in 3.65 moles of phosphorus triiodide.
To convert atoms to moles, you divide by Avogadro's number, which is approximately 6.022 x 10^23. Therefore, 1.20x10^25 atoms of phosphorus is equal to 20 moles of phosphorus.
There are 1 mol of phosphorus atoms in 1 mol of copper (II) phosphate. Therefore, in 3.30 mol of copper (II) phosphate, there are 3.30 mol of phosphorus atoms, which is equivalent to 3.30 x 6.022 x 10^23 = 1.97 x 10^24 atoms of phosphorus.
The prefix deca- means 10, so there are 10 oxygen atoms in a molecules of tetraphosphorus decoxide. The formula is P4O10
The ratio of phosphorus atoms to oxygen atoms in a compound can vary depending on the specific compound. For example, in phosphorus pentoxide (P4O10), the ratio is 4:10.
There are 2.21 x 10^24 atoms of phosphorus in 3.65 moles of phosphorus triiodide.
There are 6.022 x 10^23 atoms in one mole of phosphorus.
To convert atoms to moles, you divide by Avogadro's number, which is approximately 6.022 x 10^23. Therefore, 1.20x10^25 atoms of phosphorus is equal to 20 moles of phosphorus.
There are 1 mol of phosphorus atoms in 1 mol of copper (II) phosphate. Therefore, in 3.30 mol of copper (II) phosphate, there are 3.30 mol of phosphorus atoms, which is equivalent to 3.30 x 6.022 x 10^23 = 1.97 x 10^24 atoms of phosphorus.
Simple. 3 * 6.022 X 10^23 = 1.81 X 10^24 atoms of P
The prefix deca- means 10, so there are 10 oxygen atoms in a molecules of tetraphosphorus decoxide. The formula is P4O10
The ratio of phosphorus atoms to oxygen atoms in a compound can vary depending on the specific compound. For example, in phosphorus pentoxide (P4O10), the ratio is 4:10.
For the isotope plutonium-239: cca. 2,52.1021atoms.
To determine the number of phosphorus atoms in 30.973 grams, you would first convert the mass to moles using the molar mass of phosphorus (30.973 g/mol). Then, you would use Avogadro's number (6.022 x 10^23 atoms/mol) to find the number of phosphorus atoms, which would be 30.973 grams / 30.973 g/mol * 6.022 x 10^23 atoms/mol.
The formula for Phosphorus(V) Oxide [which has 10 oxygen atoms in a molecule] is P4O10.
There are 1 atom of phosphorus in each formula unit of copper(II) phosphate, which is Cu3(PO4)2. Therefore, in 4.40 mol of copper(II) phosphate, there are 4.40 mol of phosphorus atoms, which is 4.40 x 6.022 x 10^23 atoms.
There are 4.54 x 10^24 atoms in 7.52 moles of Phosphorus because 1 mole of Phosphorus contains 6.022 x 10^23 atoms. Multiplying this by the number of moles gives the total number of atoms in 7.52 moles.