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How many atoms are there in 5.10 grams of Phosphorus?

There are 5.10 grams of Phosphorus, which has a molar mass of approximately 30.97 g/mol. This would be approximately 0.165 moles of Phosphorus. There are approximately 6.022 x 10^23 atoms in a mole, so 5.10 grams of Phosphorus would contain approximately 9.92 x 10^22 atoms.


How many phosphorus atoms are contained in 158 kg of phosphorus?

To calculate the number of phosphorus atoms in 158 kg of phosphorus, we first need to determine the number of moles of phosphorus in 158 kg using the molar mass of phosphorus. Then we can use Avogadro's number (6.022 x 10^23 atoms per mole) to convert moles of phosphorus to atoms. The final calculation will give us the total number of phosphorus atoms in 158 kg.


How many moles of phosphorus atoms are there in 8 moles of P4O10?

Since 14 (4+10) moles of P4O10 contains 4 moles of Phosphorus, 8 moles of P4O10 will contain :: (8 x 4)/14 = 2.286 moles of Phosphorus


What is the mass of 7.21 x 1024 atoms P?

To find the mass of 7.21 x 10^24 atoms of phosphorus (P), you need to know the atomic mass of phosphorus. The atomic mass of phosphorus is approximately 31 grams per mole. By calculating the molar mass and dividing it by Avogadro's number, you can determine the mass of 7.21 x 10^24 atoms of phosphorus.


How many atoms are there in 7.52 moles of Phosphorus?

There are 4.54 x 10^24 atoms in 7.52 moles of Phosphorus because 1 mole of Phosphorus contains 6.022 x 10^23 atoms. Multiplying this by the number of moles gives the total number of atoms in 7.52 moles.

Related Questions

How many atoms in one mole of phosphorus?

6.02 x 1023


How many atoms of Hydrogen are found in 1 mole?

1 mole of any element = 6.02 × 1023 atoms


How many atoms are there in 5.10 grams of Phosphorus?

There are 5.10 grams of Phosphorus, which has a molar mass of approximately 30.97 g/mol. This would be approximately 0.165 moles of Phosphorus. There are approximately 6.022 x 10^23 atoms in a mole, so 5.10 grams of Phosphorus would contain approximately 9.92 x 10^22 atoms.


How many atoms in one mole of phosphorus vapour?

Avogadro's number: 6.02 × 1023. A mole of anything is Avogadro's number.


Avogadros number of phosphorus P atoms would have a mass of?

By saying Avogadro's number of atoms, you are saying one mole (or 6.02 × 1023 atoms). And one mole of any elements is its atomic mass. Phosphorus' atomic mass is 31.0 grams


How many phosphorus atoms are contained in 158 kg of phosphorus?

To calculate the number of phosphorus atoms in 158 kg of phosphorus, we first need to determine the number of moles of phosphorus in 158 kg using the molar mass of phosphorus. Then we can use Avogadro's number (6.022 x 10^23 atoms per mole) to convert moles of phosphorus to atoms. The final calculation will give us the total number of phosphorus atoms in 158 kg.


How many moles of phosphorus atoms are there in 8 moles of P4O10?

Since 14 (4+10) moles of P4O10 contains 4 moles of Phosphorus, 8 moles of P4O10 will contain :: (8 x 4)/14 = 2.286 moles of Phosphorus


What is the mass of 7.21 x 1024 atoms P?

To find the mass of 7.21 x 10^24 atoms of phosphorus (P), you need to know the atomic mass of phosphorus. The atomic mass of phosphorus is approximately 31 grams per mole. By calculating the molar mass and dividing it by Avogadro's number, you can determine the mass of 7.21 x 10^24 atoms of phosphorus.


How many atoms are there in 7.52 moles of Phosphorus?

There are 4.54 x 10^24 atoms in 7.52 moles of Phosphorus because 1 mole of Phosphorus contains 6.022 x 10^23 atoms. Multiplying this by the number of moles gives the total number of atoms in 7.52 moles.


How many moles of oxygen are in one mole of P4O10?

There are 10 moles of oxygen in one mole of P4O10. This is because each molecule of P4O10 contains 4 phosphorus atoms and 10 oxygen atoms.


1.50 moles of h3po4 have how many atoms of p?

each mol of h3po4 has 6.022*10^23 molecules you have 1.5 mol, so 1.5 * 6.022*10^23 molecules = 9.033*10^23 molecules each molecule of h3po4 has 1 atom of p, so you have 9.033*10^23 atoms p.


How many grams of naturally occurring phophorus must one have in order to have one mole of phosphorus?

One mole of phosphorus, which has a molar mass of about 31 grams per mole, contains 31 grams of naturally occurring phosphorus.