6.022*1023
There are 5.10 grams of Phosphorus, which has a molar mass of approximately 30.97 g/mol. This would be approximately 0.165 moles of Phosphorus. There are approximately 6.022 x 10^23 atoms in a mole, so 5.10 grams of Phosphorus would contain approximately 9.92 x 10^22 atoms.
To calculate the number of phosphorus atoms in 158 kg of phosphorus, we first need to determine the number of moles of phosphorus in 158 kg using the molar mass of phosphorus. Then we can use Avogadro's number (6.022 x 10^23 atoms per mole) to convert moles of phosphorus to atoms. The final calculation will give us the total number of phosphorus atoms in 158 kg.
Since 14 (4+10) moles of P4O10 contains 4 moles of Phosphorus, 8 moles of P4O10 will contain :: (8 x 4)/14 = 2.286 moles of Phosphorus
To find the mass of 7.21 x 10^24 atoms of phosphorus (P), you need to know the atomic mass of phosphorus. The atomic mass of phosphorus is approximately 31 grams per mole. By calculating the molar mass and dividing it by Avogadro's number, you can determine the mass of 7.21 x 10^24 atoms of phosphorus.
There are 4.54 x 10^24 atoms in 7.52 moles of Phosphorus because 1 mole of Phosphorus contains 6.022 x 10^23 atoms. Multiplying this by the number of moles gives the total number of atoms in 7.52 moles.
6.02 x 1023
1 mole of any element = 6.02 × 1023 atoms
There are 5.10 grams of Phosphorus, which has a molar mass of approximately 30.97 g/mol. This would be approximately 0.165 moles of Phosphorus. There are approximately 6.022 x 10^23 atoms in a mole, so 5.10 grams of Phosphorus would contain approximately 9.92 x 10^22 atoms.
Avogadro's number: 6.02 × 1023. A mole of anything is Avogadro's number.
By saying Avogadro's number of atoms, you are saying one mole (or 6.02 × 1023 atoms). And one mole of any elements is its atomic mass. Phosphorus' atomic mass is 31.0 grams
To calculate the number of phosphorus atoms in 158 kg of phosphorus, we first need to determine the number of moles of phosphorus in 158 kg using the molar mass of phosphorus. Then we can use Avogadro's number (6.022 x 10^23 atoms per mole) to convert moles of phosphorus to atoms. The final calculation will give us the total number of phosphorus atoms in 158 kg.
Since 14 (4+10) moles of P4O10 contains 4 moles of Phosphorus, 8 moles of P4O10 will contain :: (8 x 4)/14 = 2.286 moles of Phosphorus
To find the mass of 7.21 x 10^24 atoms of phosphorus (P), you need to know the atomic mass of phosphorus. The atomic mass of phosphorus is approximately 31 grams per mole. By calculating the molar mass and dividing it by Avogadro's number, you can determine the mass of 7.21 x 10^24 atoms of phosphorus.
There are 4.54 x 10^24 atoms in 7.52 moles of Phosphorus because 1 mole of Phosphorus contains 6.022 x 10^23 atoms. Multiplying this by the number of moles gives the total number of atoms in 7.52 moles.
There are 10 moles of oxygen in one mole of P4O10. This is because each molecule of P4O10 contains 4 phosphorus atoms and 10 oxygen atoms.
each mol of h3po4 has 6.022*10^23 molecules you have 1.5 mol, so 1.5 * 6.022*10^23 molecules = 9.033*10^23 molecules each molecule of h3po4 has 1 atom of p, so you have 9.033*10^23 atoms p.
One mole of phosphorus, which has a molar mass of about 31 grams per mole, contains 31 grams of naturally occurring phosphorus.