7.21 X 10^24 atoms phosphorous (1 mole P/6.022 X 10^23)(30.97 grams/1 mole P)
= 371 grams of phosphorous
In order to figure out how many atoms are in each sample, you would take 45, multiply it by 6.02 × 1023, and divided by the atomic mass. Since two of the numbers (45 and 6.02 × 1023) will be constants in all of the samples, the number of atoms will differ in each sample due to the atomic mass. 45 × (6.02 × 1023) / atomic mass in grams = number of atoms You could punch out all the numbers to see which sample has the greatest number of atoms, but it is easier to find the atomic mass for all of them and see which one is smaller. A larger atomic mass will mean the equation will be divided by a larger number, meaning the number of atoms will be smaller. So the smallest atomic mass would yield more atoms.Atomic masses:Mg- 24.3 grams***F- 38.0 gramsP- 31.0 gramsNa- 23.0 grams***Note that fluorine is a diatomic moleculeThe sample of 45 g of sodium (Na) would contain the greatest number of atoms
To calculate the number of phosphorus atoms in 158 kg of phosphorus, we first need to determine the number of moles of phosphorus in 158 kg using the molar mass of phosphorus. Then we can use Avogadro's number (6.022 x 10^23 atoms per mole) to convert moles of phosphorus to atoms. The final calculation will give us the total number of phosphorus atoms in 158 kg.
Magesium phosphide (Mg3P2) has 5 atoms: 3 from Mg and 2 from P.
Because there are three groups in substance Q and substance R, and there are three atoms in substance P.
The percent composition of P2O3 (diphosphorus trioxide) is 56.38% phosphorus (P) and 43.62% oxygen (O). This means that in a sample of P2O3, 56.38% of the mass is due to phosphorus atoms, while 43.62% is due to oxygen atoms.
The mass of 4.21 x 10^23 atoms of phosphorus (P) can be calculated by multiplying the number of atoms by the atomic mass of phosphorus. The atomic mass of phosphorus is approximately 31. Therefore, the mass of 4.21 x 10^23 atoms of phosphorus would be around 1.30 x 10^25 grams.
By saying Avogadro's number of atoms, you are saying one mole (or 6.02 × 1023 atoms). And one mole of any elements is its atomic mass. Phosphorus' atomic mass is 31.0 grams
30.97 or 31 grams The answer is the atomic weight
p = 4.5 g cm-3 length = 2.68 cm Volume = (2.68 cm)3 = 19.25 cm3 mass = 19.25 x 4.5 = 86.6 g Ar = 47.9 g/mol 86.6 g = 86.6/47.9 mol = 1.81 mol Number of atoms = 1.81 x 6.02 x 1023 = 1.09 x 1024 atoms
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Any prime number to the tenth power like 1024 or 59049.
To find the number of atoms in 5.18 grams of phosphorus (P), first determine the molar mass of phosphorus, which is approximately 30.97 g/mol. Then, calculate the number of moles in 5.18 g by dividing the mass by the molar mass: 5.18 g / 30.97 g/mol ≈ 0.167 moles. Finally, multiply the number of moles by Avogadro's number (approximately (6.022 \times 10^{23}) atoms/mol) to find the number of atoms: 0.167 moles × (6.022 \times 10^{23}) atoms/mol ≈ (1.01 \times 10^{23}) atoms.
The lowest number that has the letter P in its English spelling is "septillion" (1024).
To find the total number of atoms in 0.400 g of P₂O₅, first calculate the molar mass of P₂O₅, which is approximately 283.88 g/mol (with phosphorus (P) at about 30.97 g/mol and oxygen (O) at about 16.00 g/mol). Then, determine the number of moles in 0.400 g by dividing the mass by the molar mass: (0.400 , \text{g} \div 283.88 , \text{g/mol} \approx 0.00141 , \text{mol}). Since each molecule of P₂O₅ contains 7 atoms (2 phosphorus + 5 oxygen), multiply the moles by Avogadro's number (approximately (6.022 \times 10^{23}) atoms/mol) and then by 7, resulting in approximately (5.89 \times 10^{21}) total atoms.
Yes, a gigabyte. Byte (B) - 8 bits Kilobyte (kB) - 1024 bytes Megabyte (MB) - 1024 kB Gigabyte (GB) - 1024 MB Terabyte (TB) - 1024 GB Petabyte (PB) - 1024 TB Exabyte (EB), or (XB) - 1024 PB Zottabyte (ZB) - 1024 EB/XB Yattabyte (YB) - 1024 ZB (Data past the following line may not exist) -------------------------------------------------------------------------------------------------------- Saganbyte (SB) - 1024 YB Brontobyte (BB) -1024 SB Geopbyte (G?B) - 1024 BB Pijabyte (P?B) - 1024 G?B
Mass. 6.3 X 10^21 atoms phosphorous (1 mole P/6.022 X 10^23)(30.97 grams/1 mole P) = 0.32 grams of phosphorous -------------------------------------
From every two atoms of P, one molecule of P2O5 is formed. The relative formula mass of two atoms of P (phosphorous) is 62, whereas for one molecule of P2O5 it is 142. The mass of P2O5 formed is therefore 142/62 times the mass of P we started with. This comes out to 286.3g (to one decimal place).