5 atoms (one potassium, one chlorine and three oxygen) are there per molecule of KClO3
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∙ 11y agoThere are 5 atoms in 2KClO3, which consists of 2 potassium atoms (2K), 2 chlorine atoms (2Cl), and 3 oxygen atoms (3O) in each molecule of KClO3.
The balanced chemical equation for the decomposition of potassium chlorate (KClO3) is: 2KClO3(s) → 2KCl(s) + 3O2(g)
Potassium chlorate can be decomposed into potassium chloride and oxygen gas when heated. The chemical equation for this reaction is 2KClO3(s) → 2KCl(s) + 3O2(g).
The balanced equation for the decomposition of KClO3 to potassium chloride (KCl) and oxygen (O2) is: 2 KClO3 --> 2 KCl + 3 O2
KClO3, but, as you have found this site, it would be easier and less time consuming, if you learned how to use google, as a 5 second search could give you the answer, and it is also all over this site aswell. Anyways i hope this helped.
There are 20 atoms and there are 6 Carbon atoms, 8 Hydrogen atoms, 6 Oxygen atoms.
Heating potassium chlorate causes it to decompose into potassium chloride and oxygen gas, following the reaction: 2KClO3 -> 2KCl + 3O2. This is a common chemical reaction used to generate oxygen gas in the laboratory.
2KClO3 ----> 2KCl + 3O2
The balanced chemical equation for the decomposition of potassium chlorate (KClO3) is: 2KClO3(s) → 2KCl(s) + 3O2(g)
Potassium chlorate can be decomposed into potassium chloride and oxygen gas when heated. The chemical equation for this reaction is 2KClO3(s) → 2KCl(s) + 3O2(g).
2KClO3 ----> 2KCl + 3O2
2KClO3 ----> 2KCl + 3O2
2KClO3(s)->2KCl(s)+3O2(g)
2KClO2 + O2 = 2KClO3
The balanced equation for heated potassium chlorate decomposing into oxygen and potassium chloride is: 2KClO3(s) -> 2KCl(s) + 3O2(g)
This is a decomposition reaction, where a single compound breaks down into two or more simpler substances when heated. In this case, when 2KClO3 (potassium chlorate) is heated, it decomposes into 2KCl (potassium chloride) and 3O2 (oxygen gas).
2KClO3 + HEAT = 2 KCl + 3 O2
2KClO3==>2KCl+3O2 is the equation. so you need 4 moles of KClO3.