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2KClO3(s)->2KCl(s)+3O2(g)

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Q: Write the decomposition of H2CO3 and KClO3?
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How many moles of KClO3 on decomposition give 1 mole of oxygen?

2 grams of Oxygen can be obtained from 5 grams of KClO3 (only if the "CL" means "Cl", which is Chlorine! Remember that only the first letter of the atomic symbol is capitalized.)


What type of reaction is KCLO3 KCL plus 02?

This is a decomposition reaction. {Note that the letters "L" in the given question should be lower case "l" instead. Also, the equation as given, assuming an arrow after "KCLO3", is unbalanced.}


What volume of O2 collected at 22.0 C and 728 mm Hg would be produced by the decomposition of 8.15 g KClO3?

2.52 L


What type of reaction is represented H2CO3 to H2O plus CO2?

H2O(aq)+CO2(g)


Why does oxygen gas yield from any compound which decomposes?

This isn't true. Only a few compounds, such as hydrogen peroxide (H2O2) and potassium chlorate (KClO3) yield oxygen upon decomposition.


What is the formula for potassium chlorate?

The formula for potassium chlorate is KClO3.


What kind recation is 2KClO3 2KCl 3O2?

KClO3 - KCl + O2


Is this a chemical reaction H2OCO2--H2CO3?

You didn't write it exactly correctly (it should be H2O + CO2 --> H2CO3) but yes, when carbon dioxide dissolves in water, it forms carbonic acid.


How many milliliters of O2 will form a STP from 55.2 grams of KCLO3?

I assume you mean the decomposition reaction used to produce O2 in lab. 2KCLO3 -> 2KCl + 3O2 find moles O2 55.2 grams KClO3 (1 mole KCLO3/122.55 grams)(3 mole O2/2 mole KClO3) = 0.67564 moles O2 Now, I use the ideal gas law PV = nRT (1 atm)(V) = (0.67564 mol)(0.08206 L*atm/mol*K)(298.15 K) Volume O2 = 16.53 Liters which is 16530 milliliters ( less significant figures )


What is the reaction between h2so3 plus kclo3 equals?

KClO3+3H2SO3=KCl+3H2SO4


What is the name of the compound with the formula KClO3?

The name of the compound with the formula KClO3 is "potassium chlorate".


When 46.0 g KClO3 is heated 12.1 g O2 is formed how many grams of KCl is also formed?

The equation that describes this process is as follows: 2KClO3 ---> 2KCl + 3O2 For every 2 moles of reactants consumed 3 moles of oxygen gas are produced. 3 mol O2 / 2 mol KClO3 = x mol O2 / 12.3 mol KClO3 x = 12.3 mol x 3 mol / 2 mol = 18.45 mol Therefore, 18.5 mol (3 significant figures) of oxygen are produced by the decomposition of 12.3 mol of potassium chlorate