2KClO3(s)->2KCl(s)+3O2(g)
2.52 L
Methane gas is released, as well as carbon dioxide, during decomposition.
Synthesis and decomposition reactions are opposites. Synthesis: A + B -> C Decomposition: C -> A + B They both involve three elements or compounds, one of which is a combination of the other two. An example: N2O5 -> NO2 + NO3 Is a decomposition reaction.
a chemical decomposition reaction produced by passing an electric current through a solution containing ions is known as electrolytic decomposition reaction
yes alabaster was used to prevent decomposition or roting
2 grams of Oxygen can be obtained from 5 grams of KClO3 (only if the "CL" means "Cl", which is Chlorine! Remember that only the first letter of the atomic symbol is capitalized.)
This is a decomposition reaction. {Note that the letters "L" in the given question should be lower case "l" instead. Also, the equation as given, assuming an arrow after "KCLO3", is unbalanced.}
2.52 L
H2O(aq)+CO2(g)
This isn't true. Only a few compounds, such as hydrogen peroxide (H2O2) and potassium chlorate (KClO3) yield oxygen upon decomposition.
The formula for potassium chlorate is KClO3.
KClO3 - KCl + O2
You didn't write it exactly correctly (it should be H2O + CO2 --> H2CO3) but yes, when carbon dioxide dissolves in water, it forms carbonic acid.
I assume you mean the decomposition reaction used to produce O2 in lab. 2KCLO3 -> 2KCl + 3O2 find moles O2 55.2 grams KClO3 (1 mole KCLO3/122.55 grams)(3 mole O2/2 mole KClO3) = 0.67564 moles O2 Now, I use the ideal gas law PV = nRT (1 atm)(V) = (0.67564 mol)(0.08206 L*atm/mol*K)(298.15 K) Volume O2 = 16.53 Liters which is 16530 milliliters ( less significant figures )
KClO3+3H2SO3=KCl+3H2SO4
The name of the compound with the formula KClO3 is "potassium chlorate".
The equation that describes this process is as follows: 2KClO3 ---> 2KCl + 3O2 For every 2 moles of reactants consumed 3 moles of oxygen gas are produced. 3 mol O2 / 2 mol KClO3 = x mol O2 / 12.3 mol KClO3 x = 12.3 mol x 3 mol / 2 mol = 18.45 mol Therefore, 18.5 mol (3 significant figures) of oxygen are produced by the decomposition of 12.3 mol of potassium chlorate