This is a decomposition reaction. {Note that the letters "L" in the given question should be lower case "l" instead. Also, the equation as given, assuming an arrow after "KCLO3", is unbalanced.}
O2 is oxygen molecule; KCl is potassium chloride
Balance manganese dioxide and potassium chlorate is as follows . the formula for potassium chlorate is KClO3 and the one for manganese dioxide is MnO2.so, the reaction is :2 KClO3(s)-> 2 KCl(s)+3 O2(g).
A 1.80-gram mixture of potassium chlorate, kclo3, and potassium chloride, kcl, was heated until all of the kclo3 had decomposed the liberated oxygen, after drying, occupied 405 ml at 25C when the barometric pressure was 745 torr. This is the problem and the questions were... a. How many moles of O2 were produced? b. What percent of the mixture was KClO3? KCl? Please help!!
SynthesisWhenever 2 or more elements combine to form one compound, it is a synthesis reaction.
If potassium chlorate is contaminated with KCl, the experimental percent oxygen would likely be lower than the theoretical value because KCl does not contain oxygen. This contamination would reduce the amount of oxygen available from the potassium chlorate during the reaction, thus lowering the experimental yield of oxygen.
This chemical reaction is known as a decomposition reaction, where a single compound breaks down into two or more simpler substances. In this case, potassium chlorate (KClO3) decomposes into potassium chloride (KCl) and oxygen gas (O2).
This is a decomposition reaction. The compound potassium chlorate (KClO3) breaks down into potassium chloride (KCl) and oxygen gas (O2) when sulfur (S) is heated.
The reaction between H2SO3 and KClO3 does not occur. H2SO3 is a weak acid, and KClO3 is a salt. There is no precipitation, gas evolution, or significant heat release that would indicate a chemical reaction taking place between these two substances.
The balanced equation for this reaction is: 2 KClO3 -> KClO4 + KCl
You're asking if this is balanced: KClO3 → KCl + O2 Count up each atom of each element and make sure they're equal. On the left side, you have three oxygens. On the right, there are two. So no, this isn't quite balanced. The balanced equation is: KClO3 → KCl + (3/2) O2 Now you have three oxygens on the left side and 3/2 × 2 = 3 oxygens on the right. This is fine, but you might want a whole number mole ratio, in which case you multiply each term by 2. 2 KClO3 → 2 KCl + 3O2
This reaction is:2 KClO3 = 3 O2 + 2 KCl
2 KClO3 ------ 2KCl + 3O2 so 2 moles of KClO3 produces two mole of KCl. Therefore 0.440 moles of potassium chlorate will produce 0.44 moles of KCl - potassium chloride.
O2 is oxygen molecule; KCl is potassium chloride
The equation that describes this process is as follows: 2KClO3 ---> 2KCl + 3O2 For every 2 moles of reactants consumed 3 moles of oxygen gas are produced. 3 mol O2 / 2 mol KClO3 = x mol O2 / 12.3 mol KClO3 x = 12.3 mol x 3 mol / 2 mol = 18.45 mol Therefore, 18.5 mol (3 significant figures) of oxygen are produced by the decomposition of 12.3 mol of potassium chlorate
The actual formula is KClO3 (with a lowercase L) Balanced equation: 2KClO3 --> 2KCl + 3O2
Balance manganese dioxide and potassium chlorate is as follows . the formula for potassium chlorate is KClO3 and the one for manganese dioxide is MnO2.so, the reaction is :2 KClO3(s)-> 2 KCl(s)+3 O2(g).
To balance the equation, you need to ensure that the number of each type of atom is the same on both sides of the equation. In this case, you would need to change the coefficient of KClO3 to 2, KCl to 2, and O2 to 3 in order to balance the equation: 2KClO3 -> 2KCl + 3O2.