KClO3+3H2SO3=KCl+3H2SO4
When KClO3 is heated in the presence of MnO2, it undergoes a decomposition reaction to produce potassium chloride (KCl) and oxygen gas (O2). The manganese dioxide (MnO2) acts as a catalyst, speeding up the reaction but remains unchanged itself.
This is a decomposition reaction. The compound potassium chlorate (KClO3) breaks down into potassium chloride (KCl) and oxygen gas (O2) when sulfur (S) is heated.
The balanced equation for this reaction is: 2 KClO3 -> KClO4 + KCl
The standard molar entropy (ΔS) of potassium chlorate (KClO3) is 155 J/mol·K at 298 K.
KClO3 - KCl + O2
This is a decomposition reaction. {Note that the letters "L" in the given question should be lower case "l" instead. Also, the equation as given, assuming an arrow after "KCLO3", is unbalanced.}
This chemical reaction is known as a decomposition reaction, where a single compound breaks down into two or more simpler substances. In this case, potassium chlorate (KClO3) decomposes into potassium chloride (KCl) and oxygen gas (O2).
The balanced reaction for the decomposition of potassium chlorate (KClO3) is: 2 KClO3 -> 2 KCl + 3 O2 From the reaction, 2 moles of KClO3 produce 3 moles of O2. Calculate the moles of KClO3 in 6.125g using its molar mass. Convert moles of KClO3 to moles of O2. Use the ideal gas law to find the volume of O2 at STP (22.4 L/mol).
Balance manganese dioxide and potassium chlorate is as follows . the formula for potassium chlorate is KClO3 and the one for manganese dioxide is MnO2.so, the reaction is :2 KClO3(s)-> 2 KCl(s)+3 O2(g).
The compound formed between potassium and the chlorate ion is potassium chlorate, which has the chemical formula KClO3.
The equation that describes this process is as follows: 2KClO3 ---> 2KCl + 3O2 For every 2 moles of reactants consumed 3 moles of oxygen gas are produced. 3 mol O2 / 2 mol KClO3 = x mol O2 / 12.3 mol KClO3 x = 12.3 mol x 3 mol / 2 mol = 18.45 mol Therefore, 18.5 mol (3 significant figures) of oxygen are produced by the decomposition of 12.3 mol of potassium chlorate
The formula for potassium chlorate is KClO3.
The actual formula is KClO3 (with a lowercase L) Balanced equation: 2KClO3 --> 2KCl + 3O2
You're asking if this is balanced: KClO3 → KCl + O2 Count up each atom of each element and make sure they're equal. On the left side, you have three oxygens. On the right, there are two. So no, this isn't quite balanced. The balanced equation is: KClO3 → KCl + (3/2) O2 Now you have three oxygens on the left side and 3/2 × 2 = 3 oxygens on the right. This is fine, but you might want a whole number mole ratio, in which case you multiply each term by 2. 2 KClO3 → 2 KCl + 3O2
KClO3 --> KCl +O2 - hence the use in explosives chlorate normally made by action of Cl2 on KOH. Another contributor says:- KCl + O2 gives rise to KClO3
The percent of oxygen in KClO3 is 48.4%. This can be calculated by dividing the molar mass of oxygen in KClO3 (48 g/mol) by the molar mass of KClO3 (122.55 g/mol) and multiplying by 100%.
This chemical reaction is:2 KClO3 --------------(MnO2)---------------2 KCl + 3 O2