The standard molar entropy (ΔS) of potassium chlorate (KClO3) is 155 J/mol·K at 298 K.
When KClO3 is heated in the presence of MnO2, it undergoes a decomposition reaction to produce potassium chloride (KCl) and oxygen gas (O2). The manganese dioxide (MnO2) acts as a catalyst, speeding up the reaction but remains unchanged itself.
Delta S= Delta H
The reaction between H2SO3 and KClO3 does not occur. H2SO3 is a weak acid, and KClO3 is a salt. There is no precipitation, gas evolution, or significant heat release that would indicate a chemical reaction taking place between these two substances.
Delta G (written triangle G) = Delta H -T Delta S
To find the grams of KClO3 that reacted, we first need to determine the number of moles of O2 produced using the ideal gas law (PV = nRT). Converting the pressure to atmospheres (739 mmHg = 0.972 atm) and the temperature to Kelvin (26 °C = 299 K), we can calculate the moles of O2: [ n = \frac{PV}{RT} = \frac{(0.972 , \text{atm})(0.236 , \text{L})}{(0.0821 , \text{L·atm/(K·mol)})(299 , \text{K})} ≈ 0.0093 , \text{mol O2}. ] The decomposition reaction of KClO3 produces O2 according to the balanced equation 2 KClO3 → 2 KCl + 3 O2, indicating that 2 moles of KClO3 produce 3 moles of O2. Using stoichiometry, 0.0093 mol O2 corresponds to approximately 0.0062 mol KClO3. Finally, converting moles of KClO3 to grams (with molar mass ≈ 122.55 g/mol), we find that approximately 0.76 grams of KClO3 reacted.
2KClO3(s)->2KCl(s)+3O2(g)
2 grams of Oxygen can be obtained from 5 grams of KClO3 (only if the "CL" means "Cl", which is Chlorine! Remember that only the first letter of the atomic symbol is capitalized.)
The formula for potassium chlorate is KClO3.
Delta S represents the change in entropy of a system. In the equation delta G = delta H - T delta S, it is used to determine the contribution of entropy to the overall change in Gibbs free energy. A negative delta S value suggests a decrease in the disorder of a system.
The actual formula is KClO3 (with a lowercase L) Balanced equation: 2KClO3 --> 2KCl + 3O2
The percent of oxygen in KClO3 is 48.4%. This can be calculated by dividing the molar mass of oxygen in KClO3 (48 g/mol) by the molar mass of KClO3 (122.55 g/mol) and multiplying by 100%.
The atomicity of KClO3 is one, which means that in one molecule of KClO3, there is one atom each of potassium (K), chlorine (Cl), and oxygen (O).
The formula (not symbol) is KClO3
The change in enthalpy between products and reactants in a reaction
The chemical equation for converting potassium chlorate (KClO3) into oxygen (O2) is: 2KClO3 (s) -> 2KCl (s) + 3O2 (g). When heated, potassium chlorate decomposes into potassium chloride and oxygen gas.
The chemical formula (not equation) is KClO3
Balance manganese dioxide and potassium chlorate is as follows . the formula for potassium chlorate is KClO3 and the one for manganese dioxide is MnO2.so, the reaction is :2 KClO3(s)-> 2 KCl(s)+3 O2(g).