The balanced equation for the reaction between potassium chlorate (KClO3) and potassium chloride (KCl) in the presence of oxygen (O2) typically represents a decomposition reaction. However, KClO3 can decompose into KCl and O2 when heated. The balanced equation for this decomposition is: 2 KClO3 → 2 KCl + 3 O2.
The balanced equation for this reaction is: 2 KClO3 -> KClO4 + KCl
To find the grams of KClO3 that reacted, we first need to determine the number of moles of O2 produced using the ideal gas law (PV = nRT). Converting the pressure to atmospheres (739 mmHg = 0.972 atm) and the temperature to Kelvin (26 °C = 299 K), we can calculate the moles of O2: [ n = \frac{PV}{RT} = \frac{(0.972 , \text{atm})(0.236 , \text{L})}{(0.0821 , \text{L·atm/(K·mol)})(299 , \text{K})} ≈ 0.0093 , \text{mol O2}. ] The decomposition reaction of KClO3 produces O2 according to the balanced equation 2 KClO3 → 2 KCl + 3 O2, indicating that 2 moles of KClO3 produce 3 moles of O2. Using stoichiometry, 0.0093 mol O2 corresponds to approximately 0.0062 mol KClO3. Finally, converting moles of KClO3 to grams (with molar mass ≈ 122.55 g/mol), we find that approximately 0.76 grams of KClO3 reacted.
The reaction between H2SO3 and KClO3 does not occur. H2SO3 is a weak acid, and KClO3 is a salt. There is no precipitation, gas evolution, or significant heat release that would indicate a chemical reaction taking place between these two substances.
The standard molar entropy (ΔS) of potassium chlorate (KClO3) is 155 J/mol·K at 298 K.
O2 is oxygen molecule; KCl is potassium chloride
The chemical formula (not equation) is KClO3
The actual formula is KClO3 (with a lowercase L) Balanced equation: 2KClO3 --> 2KCl + 3O2
The balanced equation for this reaction is: 2 KClO3 -> KClO4 + KCl
The balanced chemical equation for the decomposition of potassium chlorate (KClO3) is: 2KClO3(s) → 2KCl(s) + 3O2(g)
To balance the equation, you need to ensure that the number of each type of atom is the same on both sides of the equation. In this case, you would need to change the coefficient of KClO3 to 2, KCl to 2, and O2 to 3 in order to balance the equation: 2KClO3 -> 2KCl + 3O2.
KClO3
You're asking if this is balanced: KClO3 → KCl + O2 Count up each atom of each element and make sure they're equal. On the left side, you have three oxygens. On the right, there are two. So no, this isn't quite balanced. The balanced equation is: KClO3 → KCl + (3/2) O2 Now you have three oxygens on the left side and 3/2 × 2 = 3 oxygens on the right. This is fine, but you might want a whole number mole ratio, in which case you multiply each term by 2. 2 KClO3 → 2 KCl + 3O2
This reaction is:2 KClO3 = 3 O2 + 2 KCl
Balance manganese dioxide and potassium chlorate is as follows . the formula for potassium chlorate is KClO3 and the one for manganese dioxide is MnO2.so, the reaction is :2 KClO3(s)-> 2 KCl(s)+3 O2(g).
2 to 3, because of the balanced equation:2 KClO3 --> 2 KCl + 3 O2
The oxidation number of Cl in KClO3 is +5. This is determined by assigning -2 to O and +1 to K, and then setting up an equation to find Cl's oxidation number based on the overall charge of KClO3.