(6.02*10^24)*0.44 = 2.6488*10^24
In 1 mol of any element there are 6.02*10^24 atoms.
To find the number of moles in 0.476 grams of bromine, you first need to determine the molar mass of bromine, which is approximately 79.904 g/mol. Then, you can use the formula: moles = mass (g) / molar mass (g/mol). Therefore, in this case, 0.476 grams of bromine is equivalent to 0.006 moles.
Ar of O = 16g/mol Mr of O2 = 2(16) = 32g/mol Using the formula : Number of moles = mass / Mr Number of moles = 40g / 32g/mol = 1.25mols One mole of substance contains the same number of particles as the Avogadro constant, which is 6.02 x 10^23 Number of Oxygen molecules = 1.25 x 6.02 x 10^23 = 7.525 x 10^23 Each Oxygen molecules contain two Oxygen atoms Number of Oxygen atoms = 7.525 x 10^23 = 1.505 x 10^24 atoms
First from atoms to mole (Avogadro's number)2.3*10+24 (atoms) / 6.022*10+23 (atoms/mole) = 3.82 mole Agand from mole to gram (via molar mass)3.82 mole * 107.9 g/mole = 412 g Ag
Carbon is the mineral found in coal, graphite, and diamonds. The different arrangements of carbon atoms lead to the diverse properties of these materials.
Fayetteville, Arkansas has experienced numerous tornadoes over the years. However, I recommend checking a local weather database or the National Weather Service for the most up-to-date and specific information on the exact number of tornadoes that have hit Fayetteville.
To find the number of moles of argon gas, you can use Avogadro's number, which is approximately (6.022 \times 10^{23}) atoms/mole. Divide the number of argon atoms by Avogadro's number: [ \text{moles of Ar} = \frac{7.52 \times 10^{22} \text{ atoms}}{6.022 \times 10^{23} \text{ atoms/mole}} \approx 0.125 \text{ moles} ] Thus, there are approximately 0.125 moles of argon gas.
First of all we convert the mass of leadto moles. Using the equation moles = mass(g) / Ar (Realtive atomic Mass)_. Mass( g) = 45 g Ar =~ 207 (Periodic Table). Hence moles(Pb) = 45 x 207 Moles (Pb) = 9315 moles. Next using the Avogadro number. 1 moles(of A SUBSTANCE) contains 6.022 x 10^(23) atoms. Hence number of atoms in 9315 moles = 9315 x 6.022 x 10^(23) = 5.61 x 10^(27) atoms. As a 'silly' number. 5,610,000,000,000,000,000,000,000,000 atoms.
From the Periodic Table, Argon has an atomic weight of 39.948. One mole of any element is equal to its atomic weight in grams. So 1 mole of Ar = 39.948g of Ar. Using that equality, you do the following calculation to find the number of moles of Ar in 22g of Ar: 22g Ar X 1mol Ar/39.948g Ar = 0.55mol Ar
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To calculate the number of atoms in 133g of calcium, we first need to determine the number of moles of calcium present. The molar mass of calcium is 40.08 g/mol. By dividing 133g by the molar mass of calcium, we find the number of moles. Finally, we can use Avogadro's number (6.022 x 10^23 atoms/mol) to convert moles to atoms, giving us the total number of atoms in 133g of calcium.
6.226 x 10^28 atoms of Nitrogen approximately mole = 6.226 X 10^28 objects Nitrogen exists as a diatomic molecule, so in 0.5 moles of diatomic nitrogen gas there are exactly 1 moles worth of molecules, therefore the number of atoms in 0.5 moles of nitrogen gas is equal to the value of the mole which is approximately 6.226 x 10 ^ 28 atoms
Each mole of particles have 6.02 x 10^23 particles. (3.6 x 10^20) / (6.02 x 10^23) = 0.000598 mol of Silicon Ar of Si (Silicon) = 28.1g/mol mass = number of moles x Ar mass = 0.000598 mol x 28.1g/mol = 0.0168g of silicon
2.3 × 1024 atoms of Ar
two or three
The answer is 0,0719 mol.
Remember the Equation Moles = mass(g) / Ar (Relative Atomic Mass) Algebraically rearranging mass(g) = moles X Ar We have 1 mole and from the Periodic Table the Atomic Mass of Sulphur is '32'. Hence substituting mass(g) = 1 moles X 32 mass = 32 g .
1 mole of any substance contains 6.022 x 10^(23) atoms/molecules. We have 1.5 x 10^(23) atoms Hence moles = 1.5 x 10^(23) / 6.022 x 10^(23) = 0.24908... moles(Mg) Also remember the eq'n moles = mass(g) / Ar Algebraically rearrange mass(g) = moles X Ar mass = 0.24908... X 24.3 (Ar of Mg ; from Periodic Table) Mass = 6.0528... g ~ 6 g